Perfect :)
I've been doing it wrong all the time, thinking I was improving performance.
It's good to know how things really work under the hood.
Thanks,
Ron
"Zeev Suraski" <[EMAIL PROTECTED]> schreef in bericht
news:[EMAIL PROTECTED]
> At 13:35 15/09/2005, Ron Korving wrote:
> >Hi,
> >
> >For p
At 13:35 15/09/2005, Ron Korving wrote:
Hi,
For performance' sake, I have to know if this is true:
Is it the case that when I do this:
array(0,1,2), "two" => array(4,5,6));
$one = $array["one"];
?>
That $one is not a copy, but a reference to $array["one"] and will only
become a copy when I
Hi,
For performance' sake, I have to know if this is true:
Is it the case that when I do this:
array(0,1,2), "two" => array(4,5,6));
$one = $array["one"];
?>
That $one is not a copy, but a reference to $array["one"] and will only
become a copy when I alter the contents of $one? I know this i
