Hi,
On Thu, Feb 23, 2017 at 10:10 AM, Johannes Schlüter
wrote:
> On Wed, 2017-02-22 at 15:01 +0100, Côme Chilliet wrote:
> > Hello,
> >
> > In the $_SESSION documentation we can see the following warning: "You
> > can't use references in session variables as there is no feasible way
> > to resto
On Wed, 2017-02-22 at 15:01 +0100, Côme Chilliet wrote:
> Hello,
>
> In the $_SESSION documentation we can see the following warning: "You
> can't use references in session variables as there is no feasible way
> to restore a reference to another variable."
Actually with register_globals gone tha
Hello,
In the $_SESSION documentation we can see the following warning: "You can't use
references in session variables as there is no feasible way to restore a
reference to another variable."
In our application, references where stored in the session and it *seemed to*
work fine under PHP5, and
On 22 January 2013 01:08, Clint Priest wrote:
> On 1/21/2013 12:36 PM, Richard Quadling wrote:
>
> Hello.
>
> This may have already been covered, so apologies ...
>
> With https://wiki.php.net/rfc/propertygetsetsyntax-v1.2#references,
> the return by reference is handled by the use of &get{}.
>
>
On 1/21/2013 12:36 PM, Richard Quadling wrote:
Hello.
This may have already been covered, so apologies ...
With https://wiki.php.net/rfc/propertygetsetsyntax-v1.2#references,
the return by reference is handled by the use of &get{}.
How about pass-by-reference for set{}?
It works, it was simpl
Hello.
This may have already been covered, so apologies ...
With https://wiki.php.net/rfc/propertygetsetsyntax-v1.2#references,
the return by reference is handled by the use of &get{}.
How about pass-by-reference for set{}?
Normally, a function definition dictates this.
But if $value is alread
Consider the following small test case where $y is first made to be a
reference to $x. And next, we assign a literal to $y.
Example #1:
refcount;
zval garbage;
if (type!=IS_TMP_VAR) {
value->refcount++; <- incrementing the refcount
of RHS zval
}
garbage = *va
Perfect :)
I've been doing it wrong all the time, thinking I was improving performance.
It's good to know how things really work under the hood.
Thanks,
Ron
"Zeev Suraski" <[EMAIL PROTECTED]> schreef in bericht
news:[EMAIL PROTECTED]
> At 13:35 15/09/2005, Ron Korving wrote:
> >Hi,
> >
> >For p
At 13:35 15/09/2005, Ron Korving wrote:
Hi,
For performance' sake, I have to know if this is true:
Is it the case that when I do this:
array(0,1,2), "two" => array(4,5,6));
$one = $array["one"];
?>
That $one is not a copy, but a reference to $array["one"] and will only
become a copy when I
Hi,
For performance' sake, I have to know if this is true:
Is it the case that when I do this:
array(0,1,2), "two" => array(4,5,6));
$one = $array["one"];
?>
That $one is not a copy, but a reference to $array["one"] and will only
become a copy when I alter the contents of $one? I know this i
On Sat, 30 Aug 2003 [EMAIL PROTECTED] wrote:
> Firstly, thanks for the tip.
> Secondly, since you fixed the problems I enumerated in another version,
> it would seem that my posting is relevant to development.
That's not your decision to make. It's totally irrelevant.
Derick
--
"Interpreting
Firstly, thanks for the tip.
Secondly, since you fixed the problems I enumerated in another version,
it would seem that my posting is relevant to development.
Thanks,
[EMAIL PROTECTED]
On Saturday, Aug 30, 2003, at 10:22 America/New_York, Derick Rethans
wrote:
Try PHP 5, and stop mailing those
On Sat, 30 Aug 2003 [EMAIL PROTECTED] wrote:
> The current support for references is mediocre at best. For instance:
>
> class foobar
> {
> var $variable;
>
> function foobar()
> {
> $variable = "foobar";
> }
> }
>
> //This form of new assignment shou
The current support for references is mediocre at best. For instance:
class foobar
{
var $variable;
function foobar()
{
$variable = "foobar";
}
}
//This form of new assignment should be the default
$a = & new foobar();
$b = & new foobar();
$
14 matches
Mail list logo
