>
> Is that creating an instance of the class name stored in the 0th index of
> the array $var or is it creating an instance of the class name stored in
> $var and accessing the 0th index using ArrayAccess?
>
As soon as $var gets involved, it should be prioritized above the new
operator. So it's e
Hi,
It's a common idiom in object-oriented languages to create an object and
then immediately call a method on it, such as (in C# or Java):
new DateTime ().ToString ()
However, PHP grammar does not work this way. You have to put an additional
round of parentheses around new clause, such as:
(ne
