Hi friends,
Thanks for your help.
I saw ANTLR Def Ref Guide.
I don't have much time.
I want a grammar file of any simple interpreter or compiler which is
working to get quick idea
Can anybody post it
Thanks in advance
Kiso
On Oct 15, 12:07 am, Terence Parr wrote:
> new lang impl book is what
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Tim, (Please reply to the mail group as well)
-
On Wed, Oct 14, 2009 at 4:17 PM, wrote:
> Wow! Thank you for getting back with me so soon. To clear things up, let me
> give you a for instance. This will also give you a glimps of a rule engine
> (which I think will grow in
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At 03:46 PM 10/14/2009, Bill Andersen wrote:
>On Oct 14, 2009, at 16:38 , John B. Brodie wrote:
>
> > Greetings!
> >
> > On Wed, 2009-10-14 at 16:15 -0400, Bill Andersen wrote:
> >> FYI, all. The problem described does NOT occur without rewrite =
> >> true
> >>
> > Isn't rewrite = true for Tree
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You received this message because you are s
On Oct 14, 2009, at 16:38 , John B. Brodie wrote:
> Greetings!
>
> On Wed, 2009-10-14 at 16:15 -0400, Bill Andersen wrote:
>> FYI, all. The problem described does NOT occur without rewrite =
>> true
>>
> Isn't rewrite = true for Tree grammars only? -- your rule below looks
> like a Parser rul
Tim,
Not exactly sure what you are trying to ask, but ill take a stab at
it. Im not sure what Sun's JS94 Standard is? Im guessing it has to do
with some sort of data traversal techniques. But I am unclear how
ANTLR relates, except for the fact that antlr could probably be used
to re-write this J
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On Wed, 2009-10-14 at 16:15 -0400, Bill Andersen wrote:
> FYI, all. The problem described does NOT occur without rewrite = true
>
Isn't rewrite = true for Tree grammars only? -- your rule below looks
like a Parser rule to me - altho can't really tell for sure...
> On Oct 14, 2009, a
FYI, all. The problem described does NOT occur without rewrite = true
On Oct 14, 2009, at 11:20 , Bill Andersen wrote:
> Hi folks
>
> I have this production
>
> assertion
> : sentence -> ^(ASSERTION NAME["foo"] sentence)
> ;
>
> in a tree grammar with rewrite = true. This is meant
Hello,
I am a bit new to ANTLR (I love it by the way) so if this is an obvious
question, forgive me in advance.
I am in the process of writing a rule engine. I know that Sun came up with the
JS94 standard but I have some ideas to enhance that standard. In order to do
this, I'm using AN
new lang impl book is what you want
http://pragprog.com/titles/tpdsl/language-design-patterns
also
http://www.antlr.org/wiki/display/ANTLR3/Pie
http://www.antlr.org/wiki/display/ANTLR3/LLVM
http://www.antlr.org/wiki/display/ANTLR3/Toy+ST+implementation
Ter
On Oct 13, 2009, at 11:51 PM, Siva B
I'm not sure what is going on there. I'd start by removing the
NAME["foo"] from that rule and see what happens.
You might also try including a simplified version of sentence that
continues to have that problem. In my experience, the process of
minimizing the test case to submit to the list iden
Here is the complete grammar:
grammar Test;
q : a ((b)=>NOWAY | /*nothing*/);
a : 'asd';
b : 'qwe';
fragment NOWAY: ;
'q' will accept "asd" but not "asdqwe". Am I missing something?
Yikes, that doesn't seem to work, it seems to give a normal positive
predicate for me. (Or something). But not "if a not followed by b" => a.
?
2009/10/14 Indhu Bharathi
> The other say I replied from my ipod and was not able to test it with
> ANTLR. I checked it now and the code doesn’t work
On Wed, Oct 14, 2009 at 10:49 AM, Evan Metheny wrote:
> Kiso,
>
> Look up the book "The Definitive ANTLR Reference" by Terence Parr for
> complete information on ANTLR.
>
> Check out the website specifically the wiki:
> http://www.antlr.org/wiki/display/ANTLR3/ANTLR+3+Wiki+Home
> and
> http://www
Hi folks
I have this production
assertion
: sentence -> ^(ASSERTION NAME["foo"] sentence)
;
in a tree grammar with rewrite = true. This is meant to tack a name
onto the results of parsing a 'sentence'. Thing is when I parse a
sample input I get an infinite tree that looks
The other say I replied from my ipod and was not able to test it with ANTLR.
I checked it now and the code doesn't work for me too. However you can try a
variant:
q : a ((b)=>NOWAY | /*nothing*/)
;
fragment NOWAY
: ;
Doesn’t a simple approach like the one shown below work?
r : ASSIGNMENTOP | KEYWORDMARKER
;
ASSIGNMENTOP : ':=' ;
KEYWORDMARKER : ':' ;
I assume you wa
Jim, being new to predicates I realised soon after this that you were
talking about token lookaheads. And yes I do need a syntactic lookahead (but
thas is negative). In beginner-speak, one of my "smaller" rules is
"consuming" something that should belong to a "larger" rule. This would be
correct if
Hi,
This is probably a very simple question, but I can't get syntactic
predicates to work in lexer rules:
AssignmentOperatorOrKeywordMarker
: ':=' => AssignmentOperator
| ':' => KeywordMarker
;
KeywordMarker
:':'
;
AssignmentOperator
:':='
;
What I want to achieve is to
Hi Evan -- couple more points on your xml grammar directly relating to your
questions.
1. On checking, as I suspected yesterday, the pattern:
('x'|'X') ('m'|'M') ('l'|'L')
... is not scoring a hit because the parser slurps up "xml" as a GENERIC_ID,
not as a sequence of three single-character
Just a minor fixup for anyone who stumbles on this thread. Yesterday I wrote:
>So far as I know, there is no impact of order in which the lexer and parser
>rules appear in the .g file.
... I later realized this could be misleading. I meant order of lexer rules
relative to parser rules. Ie: lex
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