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Hi,
I have to write a lexical rule such as
a: b c b
b: D | E
and I want 'b' tokens in rule 'a' to be the same. That's, when the first 'b2
in 'a' is D, then the last 'b' should be D. The same is true for E.
To provide this, do I have to write two alternatives for 'a' (that is, a: D
c D | E c E) o
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Thanks for the tips, Gavin. I ended up doing something along the lines of
your "each token keeps a list of includes" idea, with a slight modification.
I did the following:
- each token in the "main" file stays as is, just a plain CommonToken
- each token included from another stream has two additi
At 21:15 24/08/2009, Safiye Celik wrote:
>Yes, the problem was that my parser and tree grammars were not
>consistent. And the inconsistency is about the tree of below rule
>a:
>
>a : e (d^ e)* ;
>e : b | c! a c! ;
>
>How would I create the tree of a? I have no idea about dealing
>with repetitio
Yes, the problem was that my parser and tree grammars were not consistent.
And the inconsistency is about the tree of below rule a:
a : e (d^ e)* ;
e : b | c! a c! ;
How would I create the tree of a? I have no idea about dealing with
repetition of the token d, which is the root of a tree itself.
