Thank you Chris for the information. However, I think you are right in
saying that I am confused in regards to how Bison is working. After making
the modifications you suggested, nothing has changed. Here is the output
and below is the code snippets with the changes. Also, the input is a := (b
On Fri, Aug 6, 2010 at 5:17 AM, Sasan Forghani wrote:
>
> ..
> expr : expr BL_ADDOP expr
> ...
>char bufferT[6];
> ...
>$$ = bufferT;
>
$$ is a char* isn't it? In which case this assigns it to the
temporary bufferT, which is going to get wiped out as soon as it goes out of
scope.
Maybe
So in any action for a production such as the expr production and
specifically the expr : ( expr ) {some action}, specifying $$
will give expr its type.
I.E
expr : ( expr ) {$$; $$ = $2;}
On Wed, Aug 4, 2010 at 5:30 PM, Hans Aberg wrote:
> On 4 Aug 2010, at 21:48, Sasan Forghani wrote:
>
> Ho
On 5 Aug 2010, at 14:01, Sasan Forghani wrote:
So in any action for a production such as the expr production and
specifically the expr : ( expr ) {some action}, specifying
$$ will give expr its type.
Bison just implements a union, and the $$ and $k will select
the foo field of tha union.
On 4 Aug 2010, at 21:48, Sasan Forghani wrote:
How do you assign to $$. I've tried $$ = $1 or in the
( expr ) production $$ = $2; I always get an error
along the lines that $$ does not have a type.
The same $$, if not declared with %token or %type. See the
Bison manual, 3.5.2.
__
How do you assign to $$. I've tried $$ = $1 or in the ( expr
) production $$ = $2; I always get an error along the lines
that $$ does not have a type.
On Wed, Aug 4, 2010 at 2:45 PM, Chris verBurg wrote:
>
> I think I see a few issues in your code, but without the complete source I
> can't concl
I think I see a few issues in your code, but without the complete source I
can't conclusively say what your problem might be.
First:
> if(strcmp($2, "+"))
Just to be sure: you know strcmp returns 0 when the strings match, right? I
ask because it looks like you're trying to convert "+" to "add",
On 4 Aug 2010, at 18:39, Sasan Forghani wrote:
Thank you for the information. However, how does this relate to the
$ problem I am having. To be more specific, the
problem where the $ of the ASSIGNMENT production ends
up with the same value of the ( expr ) production.
It seems you have
Thank you for the information. However, how does this relate to the
$ problem I am having. To be more specific, the problem where
the $ of the ASSIGNMENT production ends up with the same value
of the ( expr ) production.
On Wed, Aug 4, 2010 at 9:04 AM, Hans Aberg wrote:
> On 4 Aug 2010, at 14:
On 4 Aug 2010, at 14:17, Sasan Forghani wrote:
I apologize for my lack of understanding. You said the next step is
to clean it up in the actions... please clarify?
When you allocate stuff using malloc, strdup, etc. when pointer is not
used anymore, to avoid memory leak, one must apply free
I apologize for my lack of understanding. You said the next step is to
clean it up in the actions... please clarify?
On Tue, Aug 3, 2010 at 6:13 PM, Hans Aberg wrote:
> You seem to do it already by the strdup(). The next step would be to clean
> it up in the actions.
>
>
> On 3 Aug 2010, at 23:
You seem to do it already by the strdup(). The next step would be to
clean it up in the actions.
On 3 Aug 2010, at 23:13, Sasan Forghani wrote:
Yes the lexer is generated by flex. In flex script, I have the
actions:
{addop} {yylval.blOperator = strdup(yytext); return BL_ADDOP;}
{identifie
On 3 Aug 2010, at 18:54, Sasan Forghani wrote:
| ( expr)
as long as there isn't ( expr ) in the input input move up without
problem.
However once input does have an ( expr) part, $1 at
the ADDOP
level has the value of $1 at the ASSIGNMENT level.
When I add
the following action to the ( e
[Please keep the cc to the list so that others may follow.]
On 3 Aug 2010, at 22:26, Sasan Forghani wrote:
Thank you for the response. However, I don't understand your second
statement about properly allocating. In the Bison script, I have
IDENTIFIER specified as type . And in the ( expr
On 3 Aug 2010, at 18:54, Sasan Forghani wrote:
I have been writing a simple compiler for a CS class and have run
into a few
problems that I can't figure out how to solve. %left does not seem
to be
working as Bison is derivating immediately.
For example:
a := b + c + d
expr : expr ADDOP e
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