Re: [Haskell-cafe] help in tree folding

On Wed, May 7, 2008 at 6:28 AM, patrik osgnach <[EMAIL PROTECTED]> wrote: > Daniel Fischer ha scritto: > > Am Dienstag, 6. Mai 2008 22:40 schrieb patrik osgnach: >> >>> Brent Yorgey ha scritto: >>> On Tue, May 6, 2008 at 8:20 AM, patrik osgnach < [EMAIL PROTECTED]> wrote:

Re: [Haskell-cafe] help in tree folding

Daniel Fischer ha scritto: Am Dienstag, 6. Mai 2008 22:40 schrieb patrik osgnach: Brent Yorgey ha scritto: On Tue, May 6, 2008 at 8:20 AM, patrik osgnach <[EMAIL PROTECTED]> wrote: Hi. I'm learning haskell but i'm stuck on a generic tree folding exercise. i must write a function of this type

Re: [Haskell-cafe] help in tree folding

Am Dienstag, 6. Mai 2008 22:40 schrieb patrik osgnach: > Brent Yorgey ha scritto: > > On Tue, May 6, 2008 at 8:20 AM, patrik osgnach <[EMAIL PROTECTED]> > > > > wrote: > >> Hi. I'm learning haskell but i'm stuck on a generic tree folding > >> exercise. i must write a function of this type > >> tree

Re: [Haskell-cafe] help in tree folding

Brent Yorgey ha scritto: On Tue, May 6, 2008 at 8:20 AM, patrik osgnach <[EMAIL PROTECTED]> wrote: Hi. I'm learning haskell but i'm stuck on a generic tree folding exercise. i must write a function of this type treefoldr::(Eq a,Show a)=>(a->b->c)->c->(c->b->b)->b->Tree a->c Tree has type data (

Re: [Haskell-cafe] help in tree folding

Luke Palmer ha scritto: On Tue, May 6, 2008 at 6:20 AM, patrik osgnach <[EMAIL PROTECTED]> wrote: Hi. I'm learning haskell but i'm stuck on a generic tree folding exercise. i must write a function of this type treefoldr::(Eq a,Show a)=>(a->b->c)->c->(c->b->b)->b->Tree a->c Tree has type data

Re: [Haskell-cafe] help in tree folding

On Tue, May 6, 2008 at 8:20 AM, patrik osgnach <[EMAIL PROTECTED]> wrote: > Hi. I'm learning haskell but i'm stuck on a generic tree folding exercise. > i must write a function of this type > treefoldr::(Eq a,Show a)=>(a->b->c)->c->(c->b->b)->b->Tree a->c > Tree has type > data (Eq a,Show a)=>Tree

Re: [Haskell-cafe] help in tree folding

On Tue, May 6, 2008 at 6:20 AM, patrik osgnach <[EMAIL PROTECTED]> wrote: > Hi. I'm learning haskell but i'm stuck on a generic tree folding exercise. i > must write a function of this type > treefoldr::(Eq a,Show a)=>(a->b->c)->c->(c->b->b)->b->Tree a->c > Tree has type > data (Eq a,Show a)=>Tr

[Haskell-cafe] help in tree folding

Hi. I'm learning haskell but i'm stuck on a generic tree folding exercise. i must write a function of this type treefoldr::(Eq a,Show a)=>(a->b->c)->c->(c->b->b)->b->Tree a->c Tree has type data (Eq a,Show a)=>Tree a=Void | Node a [Tree a] deriving (Eq,Show) as an example treefoldr (:) [] (++) []