On Tue, Oct 28, 2008 at 9:44 PM, Niklas Broberg
<[EMAIL PROTECTED]> wrote:
> On Tue, Oct 28, 2008 at 7:56 AM, Reiner Pope <[EMAIL PROTECTED]> wrote:
>> I've tried it out and it looks good so far. I had to fiddle with
>> haskell-src-ext's .cabal file to get it to install with GHC 6.10,
>> which is s
On Tue, Oct 28, 2008 at 7:56 AM, Reiner Pope <[EMAIL PROTECTED]> wrote:
> I've tried it out and it looks good so far. I had to fiddle with
> haskell-src-ext's .cabal file to get it to install with GHC 6.10,
> which is surprising since it isn't listed as a broken package... ah
> well.
Care to tell
Ooh, interesting. I'm going to look into this..
On 10/28/08, Reiner Pope <[EMAIL PROTECTED]> wrote:
> Unfortunately, I've uncovered a problem in the parser. For instance,
> with your module, [$hs|1+1*2|] evaluates to 4 rather than 3. This
> seems to be a general problem with infix operators, which
I've tried it out and it looks good so far. I had to fiddle with
haskell-src-ext's .cabal file to get it to install with GHC 6.10,
which is surprising since it isn't listed as a broken package... ah
well.
I'm able to write code like this now:
> foo x = [$vec|sin x, myFunc x, 4*5|]
Since Haskell
I've just uploaded an alpha version of the translation to hackage:
http://hackage.haskell.org/cgi-bin/hackage-scripts/package/haskell-src-meta-0.0.1
(I starting thinking after I uploaded that maybe haskell-src-th is a
better name..)
Here's one strategy for a haskell QQ:
It sounds like you're doing exactly what I'm looking for. I look forward to
more.
Reiner
On Tue, Oct 21, 2008 at 4:28 PM, Matt Morrow <[EMAIL PROTECTED]> wrote:
> > Is there a simple way to do this, i.e. using existing libraries?
>
> Yes indeed. I'll be traveling over the next two days, and am s
> Is there a simple way to do this, i.e. using existing libraries?
Yes indeed. I'll be traveling over the next two days, and am shooting
for a fully functional hackage release by mid next week.
> What I need is a Haskell expression parser which outputs values of type
> Language.Haskell.TH.Syntax.
Hi,
I have written a toy fixed-length-vector quasiquoter, so that you can write
[$vec|1,2|]
which has its type inferred as (Vec (S (S Z))) and you can write
mkVec :: Double -> Vec (S (S (S Z)))
mkVec x = [$vec|1,2,x|]
However, these above examples essentially demonstrate the entire syntax it
s
