Hi,
I have ghc 6.10.1 and gtk2hs 0.10.0 installed on my windows vista
computer. Both were installed using the installer on the webpages.
I am able to use gtk, glade etc but not sourceview or cairo. If I
compile the examples in the gtk2hs example folder, I get "not in
scope" error messages for fun
Thanks, but I want a nice solution not another, even more complicated,
workaround.
On 5 May 2009 at 17:10, Martijn van Steenbergen wrote:
> mwin...@brocku.ca wrote:
> > Hi,
> >
> > I am using parsec to parse a small programming language. The language is
> > typed and
> > I need to do some type
Hi,
I am using parsec to parse a small programming language. The language is typed
and
I need to do some type checking, too. I have decided to do the parsing and type
checking
simultaneously in the my parsec parser. This approach avoids to keep source
code positions
in the data type in order to
I am using GHC 6.8.3. The -O2 option made both runs faster but the 2 core run
is still much slower that the 1 core version. Will switching to 6.10 make the
difference?
On 3 Mar 2009 at 18:46, Svein Ove Aas wrote:
> On Tue, Mar 3, 2009 at 6:41 PM, Don Stewart wrote:
> > allbery:
> >> On 2009 Mar
It gets a bit faster in general but the problem remains. I have two
threads in both runs, once I use 1 core and then 2 cores. The second
run is much slower.
On 3 Mar 2009 at 17:32, Sebastian Sylvan wrote:
>
>
>
> On Tue, Mar 3, 2009 at 5:31 PM, wrote:
> In both runs the same computations
In both runs the same computations are done (sequentially resp.
parallel), so the gc should be the same. But still using 2 cores is
much slower than using 1 core (same program - no communication).
On 3 Mar 2009 at 20:21, Bulat Ziganshin wrote:
> Hello mwinter,
>
> Tuesday, March 3, 2
Hi,
I tried a get into concurrent Haskell using multiple cores. The program below
creates 2 task in different threads, executes them, synchronizes the threads
using MVar () and calculates the time needed.
import System.CPUTime
import Control.Concurrent
import Control.Concurrent.MVar
myTask1 =
