scheme@(guile-user)> (define (foo2) (define x 7) (defined-symbol? x))
scheme@(guile-user)> (foo2)
$2 = #t
On Tue, Apr 16, 2024 at 8:36 AM Damien Mattei
wrote:
> this could not works because the defined-symbol? used in the macro
> if-defined return false because at the expansion of the macro the
this could not works because the defined-symbol? used in the macro
if-defined return false because at the expansion of the macro the symbol is
not defined.
Instead at run-time, this works:
#|kawa:21|# (define (foo2) (define x 7) (defined-symbol? x))
#|kawa:22|# (foo2)
#t
On Sun, Apr 14, 2024 at
i tried this, that works in some case:
;; scheme@(guile-user)> (defined-symbol? d)
;; ;;; :20:17: warning: possibly unbound variable `d'
;; $3 = #f
(define-syntax defined-symbol?
(syntax-rules ()
((_ x) (call-with-current-continuation
(lambda (exit)
(with-exception-handler
(lam
indeed ,seems not a thing feasible ,unless in Racket where it works great:
https://stackoverflow.com/questions/3267351/how-do-i-test-whether-a-variable-is-defined-before-referencing-it?noredirect=1&lq=1
On Fri, Apr 12, 2024 at 12:34 AM Damien Mattei
wrote:
>
> hello,
>
> i'm searching the equiv
