I know this is wrong
Would someone fix it
.ds a foo
.ds b bar
.
.if d a & d b \{\
\*[a] \*[b]
.\}
Richard
> I know this is wrong
> Would someone fix it
>
> .ds a foo
> .ds b bar
> .
> .if d a & d b \{\
> \*[a] \*[b]
> .\}
>
> Richard
>
Solution:
.ds a foo
.ds b bar
.
.if d a \
. if d b \{\
\*[a] \*[b]
.\}
>From groff.info, section `Operators in Conditionals':
Note that these operators [like `
> Can you please adjust my `R' file to
> trigger the bug or problem?
Use a line length of 1.6 inches.
By the way: instead of \h'0' you can also use \v'0', \X'',
or probably a lot of other things that put "something else"
in the output.
By the way 2: instead of setting a register to the current
On Tue, 6 Apr 2010, Werner LEMBERG wrote:
I know this is wrong
Would someone fix it
.ds a foo
.ds b bar
.
.if d a & d b \{\
\*[a] \*[b]
.\}
Richard
Solution:
.ds a foo
.ds b bar
.
.if d a \
. if d b \{\
\*[a] \*[b]
.\}
From groff.info, section `Operators in Conditionals':
Note that t
On 06-Apr-10 13:54:31, Richard Ray wrote:
> I know this is wrong
> Would someone fix it
>
> .ds a foo
> .ds b bar
> .
> .if d a & d b \{\
> \*[a] \*[b]
> .\}
>
> Richard
The following works:
.ds a foo
.ds b bar
.if d a \{\
.if d b \{\
\*[a] \*[b]
.\}
.\}
(You can test it by following ".ds b ba
I want to pass multiple arguments to a macro and each argument may be
composed of multiple words/characters
I figured out this works but is there a way without defining individual
strings
.nf
.de P
\\*[\\$1]
\\*[\\$2]
\\*[\\$3]
..
.
.ds x a b c
.ds y d e
.ds z f g h i
.P x y z
Richard
> I want to pass multiple arguments to a macro and each argument may be
> composed of multiple words/characters
> I figured out this works but is there a way without defining individual
> strings
>
> [snip]
Put the arguments in double quotes, like this:
.de P
1 = \\$1
2 = \\$2
3
I don't know if I'm missing something obvious in the question...
If your source file defines macro P as stated, why not:
.de P
\\$1 \\$2 \\$3
..
then in the text file:
.P "a b c" "d e" "f g h i"
Whitespace is inserted by the macro between \\$1, \\$2, and \\$3.
This is similar to how it's don
