(part 2)
...sorry, I should have said:
"f() will complete its evaluation before g() is runnable, it g() runs at
all."
"g() will become runnable before evaluation of f() is started"
"f() will evaluate completely and then g() will evaluate completely before
func() returns"
On Tue, Oct 10, 2017 a
First...
go func() {
f()
go g()
}()
is tremendously different than:
go func() {
go g()
f()
}()
and neither is equivalent to :
go func() {
f()
g()
} ()
...and on the order of evaluation and visibility and weak memory coher
