ray), “<-done” (break), and
> “<-timeout” (break). After the loop, send the array.
>
>
>
> John
>
> John Souvestre - New Orleans LA
>
>
>
> *From:* desaia...@gmail.com [mailto:de...@gmail.com
> ]
> *Sent:* 2017 January 08, Sun 07:10
> *To:* John So
The ran the code on play, seems to come out within 2 seconds.
https://play.golang.org/p/yZIAvXI8IX
On Sun, Jan 8, 2017 at 12:53 PM, wrote:
>
> Can you please help to correct below program where timeout not seems
> working
>
> Work 1 - have 1 second
> Work 2 - have 3 second
> Total Timeout - 2 s
...@souvestre.com]
Sent: 2017 January 08, Sun 07:27
To: 'golang-nuts'
Subject: RE: [go-nuts] Multiple goroutine timeout for waitgroup not working
Hi Abhi.
I’m thinking something like this might do the job. Call monitorWorker(wg,
done) as a goroutine and change it to do just the wg.Wait t
desaiabhi...@gmail.com]
Sent: 2017 January 08, Sun 07:10
To: John Souvestre
Cc: golang-nuts
Subject: Re: [go-nuts] Multiple goroutine timeout for waitgroup not working
Hi John
Can you please help me to apply correct logic to achieve it
Haven't found any solution on the net. All articles are
; Sent: 2017 January 08, Sun 06:24
> To: golang-nuts
> Subject: Re: [go-nuts] Multiple goroutine timeout for waitgroup not working
>
> hi John
>
> I am expecting work2 should not include in
>
> headers = <-messgesResponse
>
> so output of
: Re: [go-nuts] Multiple goroutine timeout for waitgroup not working
hi John
I am expecting work2 should not include in
headers = <-messgesResponse
so output of below should be Len = 1 and should print only work 1 only and not
2 ( as work 2 is timed out )
fmt.Pri
se, and it is taking place.
>
> What were you expecting to see?
>
> John
>
> John Souvestre - New Orleans LA
>
> From: golang-nuts@googlegroups.com [mailto:golang-nuts@googlegroups.com] On
> Behalf Of desaiabhi...@gmail.com
> Sent: 2017 January 08, Sun 05:4
expecting to see?
>
>
>
> John
>
> John Souvestre - New Orleans LA
>
>
>
> *From:* golan...@googlegroups.com [mailto:
> golan...@googlegroups.com ] *On Behalf Of *
> desaia...@gmail.com
> *Sent:* 2017 January 08, Sun 05:48
> *To:* golang-nuts
> *S
-nuts'
Subject: RE: [go-nuts] Multiple goroutine timeout for waitgroup not working
Hi Abhi.
I believe that the wait group timeout (in monitorWorker) was set to 2 seconds
in the code you posted.
I put a debugging print in the timeout case, and it is taking place.
What were you ex
@googlegroups.com [mailto:golang-nuts@googlegroups.com] On
Behalf Of desaiabhi...@gmail.com
Sent: 2017 January 08, Sun 05:48
To: golang-nuts
Subject: Re: [go-nuts] Multiple goroutine timeout for waitgroup not working
hi John
Thanks for the reply
sorry
I mean Work2 takes => 3 seco
hi John
Thanks for the reply
sorry
I mean Work2 takes => 3 seconds
work1 takes => 1 seconds
Wait group timeout is => 1 seconds
It is expected that only Work1 should get done and Work 2 should get
timeout which is not happening
Waitgroup waits for both work.. program doing something wrong
f
Thanks for the reply Sairam
Problem is if I change Work2 time => 3 sec then that work should get
timeout but program still returning it
func Work2(message chan *TestStruct, wg *sync.WaitGroup, tokenNumber
string) {
defer wg.Done()
v1 := new(TestStruct)
v1.Name = tokenNumber
time.Sleep(3 * time.
What do you see when you run it? I see:
finished 1
finished 2
len > %!s(int=2) ç Using a string format for an int
Name > 1
Name > 2
Ø Work 2 - have 3 second
I’m not sure exactly what you are trying to do, but I suspect that changing
“messges” to hold 2 items might
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