I guess I have misunderstood something about the process of the allocation
and gc :) Maybe I need to learn from the gc theory first. BTW thanks for
your reply.
在2021年3月20日星期六 UTC+8 上午1:20:12 写道：
> On Thu, Mar 18, 2021 at 8:36 PM Paul Zhang wrote:
> >
> > Can I just understand that for the defa
On Thu, Mar 18, 2021 at 8:36 PM Paul Zhang wrote:
>
> Can I just understand that for the default case, when the compiler executes
> the mallocgc() for c.buf, it would use reflect to build the descriptor for
> the type of element? And if it allocates the both spaces in one function
> call, it wo
AFAIK when there's no pointer in elem (the channel's element's type), we
can cheat/optimize (call as you wish),
and allocate the channel's backing memory AND all it's elements' memory at
once, AS A BYTE ARRAY (nil is the second argument of mallocgc).
Then we can play unsafe tricks an treat it as
On Fri, Mar 19, 2021 at 4:36 AM Paul Zhang wrote:
Please do not post colorized code to the ML. Particularly with
inverted colors. Please use plain black on white text, thank you.
--
You received this message because you are subscribed to the Google Groups
"golang-nuts" group.
To unsubscribe fr
For this piece of code:
case elem.ptrdata == 0:
// Elements do not contain pointers.
// Allocate hchan and buf in one call.
c = (*hchan)(mallocgc(hchanSize+mem, nil, true))
c.buf = add(unsafe.Pointer(c), hchanSize)
default:
// Elements contain pointers.
c = new(hchan)
c.buf =
On Thu, Mar 18, 2021 at 9:55 AM Paul Zhang wrote:
>
> I was reading the source code of makechan(), and these questions confused me.
> I would appreciate it if someone could help me.
>
> Q1. What does Elements do not contain pointers. mean? Does that means that
> the type of channel is not a poin
I was reading the source code of makechan(), and these questions confused
me. I would appreciate it if someone could help me.
Q1. What does Elements do not contain pointers. mean? Does that means that
the type of channel is not a pointer type (like chan int and chan *int)?
Q2. Why does the allo
