Thanks, folks!
It's clear now:
func sock() {
conn, err := net.Dial("tcp", "192.168.0.1:80")
if err != nil {
fmt.Printf("\nDial has an error for you: %v\n", err)
return
}
fmt.Fprintf(conn, "GET / HTTP/1.0\r\n\r\n")
status, err := bufio.NewReader(conn).ReadString('\n')
fmt.Printf
Your printf does not include a newline character, so the panic message is
from your usage of conn in the line
fmt.Fprintf(conn, "GET / HTTP/1.0\r\n\r\n")
Because an error occured during the dail, you cannot use or assume conn has
any sensible value.
On Sunday, 11 December 2016 21:43:02 UTC+11,
I've modified the function accordingly:
func sock() {
conn, err := net.Dial("tcp", "192.168.0.1:9991")
if err != nil {
fmt.Printf("\nDial has an error for you %v", err)
}
fmt.Fprintf(conn, "GET / HTTP/1.0\r\n\r\n")
status, err := bufio.NewReader(conn).ReadString('\n')
fmt.Printf("
On a Dial error conn will be nil. Remove the call to conn.Close()
On Saturday, 10 December 2016 23:28:36 UTC, Stannis Kozlov wrote:
>
> I'm trying to write simple port scanner and using "net" to check port
> availability:
> func sock() {
> conn, err := net.Dial("tcp", "192.168.0.1:9991")
> if
conn is probably nil if there is an error. Call Close only if there is no
error.
conn, err := net.Dial(...)
if err != nil {
// handle error
}
defer conn.Close()
Am Sonntag, 11. Dezember 2016 00:28:36 UTC+1 schrieb Stannis Kozlov:
>
> I'm trying to write simple port scanner and using "net" to
