lly at any time without
> 18 // notification. If the Pool holds the only reference when this
> happens, the19 // item might be deallocated.
>
> So placing an object in the pool does not guarantee it won’t be collected
> - causing a future allocation.
>
> On Mar 25, 2020, a
chunkCrc32Hash := crc32.NewIEEE()
chunkBuf := bufferpool.GetInstance().Get()
//回收buffer
defer bufferpool.GetInstance().Put(chunkBuf)
writer := io.MultiWriter(chunkBuf, chunkCrc32Hash)
_, copyErr := io.Copy(writer, chunkResp.RawResponse.Body)
if copyErr != nil && copyErr != io.EOF {
logmgr.ErrorL
There is not any guarentee in your goroutine, But you could try it
as:https://play.golang.org/p/JDRAP4mxdc
On Friday, November 11, 2016 at 2:08:39 PM UTC+8, mspaul...@gmail.com wrote:
>
> Hello,
>
> I've written a small program to demonstrate what I am seeing. If I use a
> channel as a semap
t; The code that is generated is exactly the same for both (you can check
> this with go tool compile -S).
>
> On Thu, 2016-11-10 at 23:46 -0800, steve tang wrote:
> > Thanks, But I want them hold same data addrs. So I just changed
> > your code
> > to follows:
main
>
> import (
> "fmt"
> )
>
> func main() {
> a := [3]int{1, 2, 3}
> b := a[:]
> fmt.Println(b)
> }
>
> https://play.golang.org/p/OBY7g3azBE
>
> If so, there's no need for unsafe. If not, what are y
Hi theres,
I used unsafe.Pointer to conv Type [3]int to Type []int, But it throws
a runtime error, Could anybody tell me why? many thanks. The test code is
as follows:
package main
import (
"fmt"
"unsafe"
)
func main() {
a := [3]int{1, 2, 3}
b := *(*[]int)(unsafe.Pointer(&a))
fmt.Print
