Hi, maybe it's because no goroutine read the channel, the four value
cause the deadlock because for write that value there is no space in the
channel, sorry by my English, I'm new in go too...
El mar., 29 ene. 2019 9:55, 伊藤和也 escribió:
> I know the general meaning of a deadlock, but I don't k
> On Thu, Jan 24, 2019 at 7:12 PM diego patricio wrote:
>
>> Hi all, i'am just learning Go and goroutines, I have three goroutines
>> (main, producer, consumer) and I dont know how synchronize producer and
>> consumer for print one value at time, the output that
fmt.Printf("Consumer %v\n", i)
> }
>
> ..but I imagine that's not the point of the excercise.
>
> -Ian
>
> Quoting diego patricio (2019-01-24 16:48:35)
> >Hi, thanks for your response, still� I dont get right result
> >image.png
>
channel. you have used a buffered channel of 1.
>
> Sent from my iPhone
>
> On 24. Jan 2019, at 22:11, diego patricio wrote:
>
> Hi all, i'am just learning Go and goroutines, I have three goroutines
> (main, producer, consumer) and I dont know how synchronize producer and
Hi all, i'am just learning Go and goroutines, I have three goroutines
(main, producer, consumer) and I dont know how synchronize producer and
consumer for print one value at time, the output that I want is
Producer 0
Consumer 0
Producer 1
Consumer 1
..
but the output of my program it's diferen
>From stackoverflow, i think that is a proper explanation
[image: image.png]
https://stackoverflow.com/questions/35983118/what-does-nil-mean-in-golang
Regards
El lun., 21 ene. 2019 a las 14:19, 伊藤和也 ()
escribió:
> So what do you think "nil" represents instead?
> "nil" is just a special value?
