ype definition creates a new, distinct type with the same underlying
> type <https://golang.org/ref/spec#Types> and operations as the given
> type, and binds an identifier to it."
>
> myInt is a distinct type from int, but it has the same underlying type and
> is therefore "num
.
On Sunday, February 18, 2018 at 2:16:17 PM UTC-5, Jan Mercl wrote:
>
> On Sun, Feb 18, 2018 at 8:06 PM Bill Wood >
> wrote:
>
> > I thought that the plus operator would return an int, not a myInt.
>
> expr1 + expr2 works iff types of expr1 and expr2 are the same and th
s interface{} = res; // no cast needed, see above
> return ires
> }
>
> Hope this clarifies the typing.
>
> Aside: if you come from C++, aliasing interface{} as any might feel
> comfortable, but that's not a good Go style.
>
>
> On Saturday, February 17, 2018 at
HI, Go newbie here... not sure if this is a dumb question or not :)
I have a simple program:
package main
import "fmt"
type any interface{}
type myInt int
func plus(a, b any) any { return a.(myInt) + b.(myInt) }
func main() {
s := plus(myInt(3), myInt(2))
fmt.Printf("%v, %T\n", s, s)
}
Outp
