On Mon, Sep 6, 2021 at 7:40 PM 'nadashin' via golang-nuts <
golang-nuts@googlegroups.com> wrote:
> Why is the function in Go compiler that interprets escape sequences not
> available in Go's standard library?
>
It does. See https://pkg.go.dev/strconv#Unquote. Try this hastily thrown
together exam
Why is the function in Go compiler that interprets escape sequences not
available in Go's standard library?
--
You received this message because you are subscribed to the Google Groups
"golang-nuts" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to golang
If the growing function is currently
f(x) = 2x for x < 1024
f(x) = x + x/4 otherwise
(Which I haven't checked), couldn't a simple way be to use e.g.
f(x) = 2xfor x < 1024
f(x) = x + x/4 + 768 otherwise
Then
f(1023) = 2046
f(1024) = 2048
So the function is monotonic
I don't think this is an important thing to fix, but I agree it is a bit
odd. If there's a simple way to restore monotonicity we'll consider it.
A similar issue: https://github.com/golang/go/issues/41239
On Sunday, September 5, 2021 at 8:59:01 AM UTC-7 jake...@gmail.com wrote:
> You are 100% cor
