Binary identical means that the files are identical bit-for-bit, i.e.
if you ran "cmp traj1.trr traj2.trr" it would report the files to be
the same/indistinguishable.
This is normally only important for debugging. If you don't know it
doesn't apply to you :-)
All that matters for you is t
Hi,
In editconf, there's an option -center which allows you to place the
geometrical center of your molecular at a desired location.
I was wondering, is there an analogous option for the placement of the
center of mass of a molecule?
Thanks,
Arneh
__
Hi Erick,
Thank you for you responce. I am sorry but I dont unterstand the term
"_binary_ identical results". The first simulation was run on a linux machine
(pentium 4) with gromacs 3.2 from the rpm included in suse. The new machine
will be (Pentium4 Xeon) with gromacs 3.3 (manual compiled)
Hi Anthony,
As long as the version you're continuing with is the same or more
recent than the one you started with it should work fine; all gromacs
output files are stored in portable formats and are can be read by
newer versions.
You are not guaranteed _binary_ identical results, though
Hi users:
I have made some simulation in one of our workstation. Now I want to extend
the simulations few nanoseconds. I can continue the simulations in other
machine without affecting the results? I need to use the same gromacs
version?
Best Regards,
Anthony
__
Ramya,
A timestep of dt=0.002 already means a timestep of 2fs, since the unit
of dt is ps. So a timestep of dt=0.002=2 fs works fine for you, which is
perfectly normal. If you want to go higher you need to use certain
tricks, as suggested by Xavier.
I suggest you read the manual (e.g.
http://www.
Hi,
In principle Gromacs should never just crash with a segmentation
fault, but at least give you a (perhaps cryptic) error message and
exit somewhat gracefully.
As far as I know there is only one exception to this: If you are
using tabulated interactions the table can only be of finite s
It is not possible to answer your question from the information you give.
A lot of things can cause a segmentation fault. From compilation to
your particular system. Put a search on the user-list, you'll get an idea
of possible problems.
It depends what you will be looking at but I would suggest
Hello..
Thanks to Xavier for his prompt reply..
Actually my objective is a bit longer[50-60ns] but the problem is that
even if i cant change the time-step to 0.003 it is exiting saying
segmentation fault then how is it possible with 1fs [or 4 fs as
suggested] which i want to do to reduce tim
Hi,
Just to let you guys know, the 'article gallery' on the gromacs website
doesn't seem to work anymore.
mzzls
Jeroen
___
gmx-users mailing listgmx-users@gromacs.org
http://www.gromacs.org/mailman/listinfo/gmx-users
Please search the archive at h
10 ns of a solvated protein of regular size should not require much
computing time.
Increasing the time-step above 2 fs is a solution to increase the
speed of the run but then you face the problem of not integrating
the fast movement correctly and this can end up in large forces
and then you run
Did you booted your lam?
Go to a specific node of your cluster, for example node 3, and create a file
with a simple name like lamhosts. This file must contain just the nodes you
may want to boot (the name of the node, like no3, or something like this).
Than, run
lamboot lamhosts -v
If you have tw
Hello,
I am trying to perform a simulation run of 10ns for my system
[protein+waterbox].The system works fine if i use timestep[dt=0.002
fs]. To balance the run time and time-consumption, when we try a
.mdp file with slight increase of timestep i.e., to 0.003 fs; grompp
works fine and gener
pkmukher wrote:
Hi users,
I am having a problem during the running of the mdrun
program on my prepared system.I have a system containing a
protein/peptide complex. i have prepared the protein using
the pdb2gmx utility and the peptide using the PRODRG
utility. I have then included the ligand .itp
Hi everyone,
I am new to mutagenesis studies, so I was wondering if I could get some
input on my approach. My task involves mutagenizing a residue (with all 19
possibilities) in a protein that binds DNA, and then deciding whether the
resulting structure is physically acceptable.
My approach to d
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