I am looking for a way to force smudge filter to run by simulating a
real life checkout. Let's say I just created a new branch and did not
modify any files but want to test my new smudge filter. According to
some answers such as
https://stackoverflow.com/questions/22909620/git-smudge-clean-filter-b
On 9/6/16, Torsten Bögershausen wrote:
> On 06.09.16 19:47, john smith wrote:
>> I am looking for a way to force smudge filter to run by simulating a
>> real life checkout. Let's say I just created a new branch and did not
>> modify any files but want to test my new s
On 9/8/16, Jakub Narębski wrote:
> W dniu 06.09.2016 o 23:01, john smith pisze:
>
>> I'd prefer smudge/clean filters instead of `make' scripts etc. to
>> convert template dotfiles into something usable and back because
>> filters:
>>
>> 1. could be
On 9/10/16, Junio C Hamano wrote:
> The clean and smudge operations should look _only_ at the contents
> they are filtering, and nothing else, and the clean/smudge filtering
> mechanism is designed to support that use case. It is not designed
> to do things like embedding the name of the branch t
On 9/10/16, Jakub Narębski wrote:
> You would need post-checkout hook together with clean / smudge filters
> (though you could get by without smudge filter, at least in theory...).
> The `post-checkout` hook could run e.g. "git checkout -- '*.conf'"
> to force use of smudge filter, after checking
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--
To
I found that I use submodules much, much more often in my git projects than I
used externals
in Subversion and the reason is that git encourages/forces to organize large
projects into
smaller repositories, one reason for this being that subversion allows to check
out parts of
a repository while
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