Reminder that the gEDA sprint/cookout is this Saturday... So far the
weather is "chance of showers" but it may change by then.
> The usual rules apply - main event is 10am-5pm EST, stay later if
> you want, we'll provide basic eats but bring special eats if you
> want. Those who wish to attend
:SetValue(Grid,=196,mil)
Alternately, use a script to generate your footprint so you can
calculate the placements programmatically.
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Hello all,
I am working on a pcb that needs 50 pin in the same line spaced .196
inch, I find to be very hard to place one pin at time at equal distance.
Is possible to set the grid to 196 mil? Then I can use the grid for
place the pin at proper distance from each other I was not able to find,
I did
Hi,
The title is quite explicit , I think :-) .
Here is the .net file I use :
* RLC serial circuit
ISRC 1 0 AC 1
C0 1 2 1Om
L0 2 3 0.1m
R0 3 0 1
Rconv 1 0 100Meg
* wcut-low = 1/(R0*C0)=100 rad/s
* wcut-high = R0/L0 =10k rad/s
.AC DEC 1 1u 1Meg
.END
plotting V(1), I thought I would
Hi r ,
Thanks, that works perfect :-)
Cédric
r wrote :
> Hi,
>
> There is no DC path from node '1' to the ground (node '0'). Add a
> large resistor between them and the simulation will work:
>
> Tranfer function
> ISRC 1 0 AC 1
> R1 1 2 1k
> C1 2 3 1u
> R2 3 0 1k
> C2 3 0 1u
> R10 1 0 1e+12
>
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