On 09/24/2015 12:29 AM, Robin Dapp wrote:
On 09/15/2015 05:25 PM, Jeff Law wrote:
On 09/15/2015 06:11 AM, Robin Dapp wrote:
Hi,
recently, I came across a problem that keeps a load instruction
in a loop although it is loop-invariant.
[..]
You might want to check your costing model -- cprop is
On 09/15/2015 05:25 PM, Jeff Law wrote:
> On 09/15/2015 06:11 AM, Robin Dapp wrote:
>> Hi,
>>
>> recently, I came across a problem that keeps a load instruction in a
>> loop although it is loop-invariant.
[..]
> You might want to check your costing model -- cprop is supposed to look
> at costs to h
On 09/15/2015 06:11 AM, Robin Dapp wrote:
Hi,
recently, I came across a problem that keeps a load instruction in a
loop although it is loop-invariant.
A simple example is:
#include
#define SZ 256
int a[SZ], b[SZ], c[SZ];
int main() {
int i;
for (i = 0; i < SZ; i++) {
a[i] = b[i]
On Tue, Sep 15, 2015 at 2:11 PM, Robin Dapp wrote:
> Hi,
>
> recently, I came across a problem that keeps a load instruction in a
> loop although it is loop-invariant.
>
> A simple example is:
>
> #include
>
> #define SZ 256
> int a[SZ], b[SZ], c[SZ];
>
> int main() {
>
> int i;
> for (i = 0;
Hi,
recently, I came across a problem that keeps a load instruction in a
loop although it is loop-invariant.
A simple example is:
#include
#define SZ 256
int a[SZ], b[SZ], c[SZ];
int main() {
int i;
for (i = 0; i < SZ; i++) {
a[i] = b[i] + c[i];
}
printf("%d\n", a[0]);
}
The re
