On 12/2/2021 7:53 PM, Eugene Rozenfeld via Gcc-patches wrote:
When a basic block A has been annotated with a count and it has only one
successor (or predecessor) B, we can propagate the A's count to B.
The algorithm without this change could leave B without an annotation if B had
other unannot
When a basic block A has been annotated with a count and it has only one
successor (or predecessor) B, we can propagate the A's count to B.
The algorithm without this change could leave B without an annotation if B had
other unannotated predecessors (or successors). For example, in the test case I
