http://gcc.gnu.org/bugzilla/show_bug.cgi?id=54823
--- Comment #5 from Sebastian Freundt 2012-10-05
12:45:45 UTC ---
Ok, I see. I assume, there's no plans on widening the allowed expressions for
constant integers?
It's autogenerated code a la:
#define foo "bar"
(foo)[1] * 0x55 +
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=54823
Jakub Jelinek changed:
What|Removed |Added
CC||jakub at gcc dot gnu.org
--- Co
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=54823
--- Comment #3 from Sebastian Freundt 2012-10-05
11:46:20 UTC ---
I'm more or less referring to the internals, why is it a constant expression in
the first case, but not treated as an integer constant expression.
Also, according to the r
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=54823
--- Comment #2 from Jonathan Wakely 2012-10-05
11:34:09 UTC ---
6.7.2.2 "The expression that defines the value of an enumeration constant shall
be an integer constant expression that has a value representable as an int."
See 6.6 for the
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=54823
--- Comment #1 from Jonathan Wakely 2012-10-05
11:29:49 UTC ---
*" " is not a constant expression according to the C standard.
The standard says "An implementation may accept other forms of constant
expressions" so ICC is allowed to acce
