https://gcc.gnu.org/bugzilla/show_bug.cgi?id=104418
--- Comment #4 from Fedor Chelnokov ---
I think `using B::B;` is not the same as redefining each constructor with the
explicit call of base class constructor `C(int a) : B{(int)a}{}`.
Please consider this example proving it:
```
struct A {
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=104418
--- Comment #3 from Andrew Pinski ---
But this is invalid code with a similar error message:
struct B {
B(int) {}
B(int&&) {}
};
struct C : B {
C(int a) : B{(int)a}{}
};
So the question is how is default constructor done, is it done
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=104418
--- Comment #2 from Fedor Chelnokov ---
My personal feeling is that if a compiler accepts `B b(i);` then it must accept
`C c(i);` as well because of [namespace.udecl] p13:
> Constructors that are named by a using-declaration are treated as thou
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=104418
--- Comment #1 from Andrew Pinski ---
MSVC and ICC reject this for the same reason as GCC. Are you sure this is not a
bug in clang?
