Hello,
RTEMS applications are usually fully statically linked together with the
operating system. So, we can use the -ftls-model=local-exec TLS model.
The default value for this option is defined in common.opt:
ftls-model=
Common Joined RejectNegative Enum(tls_model) Var(flag_tls_default)
In
Excerpts from Tulio Magno Quites Machado Filho's message of July 16, 2022 6:17
am:
> Segher Boessenkool writes:
>
>> That is a usability problem. Can it be fixed, or will that create its
>> own compatibility problems? In practice I mean. If it is, the C
>> libraries could fix it up, for new p
On 20/07/2022 10:43, Sebastian Huber wrote:
Hello,
RTEMS applications are usually fully statically linked together with the
operating system. So, we can use the -ftls-model=local-exec TLS model.
The default value for this option is defined in common.opt:
ftls-model=
Common Joined RejectNegat
On Wed, 20 Jul 2022, Sebastian Huber wrote:
> How does Ada get its default TLS model?
You shouldn't need to do anything special, GCC automatically selects
initial-exec or local-exec for non-PIC (including PIE).
Alexander
On 20/07/2022 13:41, Alexander Monakov wrote:
On Wed, 20 Jul 2022, Sebastian Huber wrote:
How does Ada get its default TLS model?
You shouldn't need to do anything special, GCC automatically selects
initial-exec or local-exec for non-PIC (including PIE).
I am not sure, for this test program:
On Wed, 20 Jul 2022, Sebastian Huber wrote:
> On 20/07/2022 13:41, Alexander Monakov wrote:
> > On Wed, 20 Jul 2022, Sebastian Huber wrote:
> >
> >> How does Ada get its default TLS model?
> > You shouldn't need to do anything special, GCC automatically selects
> > initial-exec or local-exec fo
On 20.07.22 15:01, Alexander Monakov wrote:
On Wed, 20 Jul 2022, Sebastian Huber wrote:
On 20/07/2022 13:41, Alexander Monakov wrote:
On Wed, 20 Jul 2022, Sebastian Huber wrote:
How does Ada get its default TLS model?
You shouldn't need to do anything special, GCC automatically selects
init
