On Fri, 2011-02-25 at 19:57 +, Dave Korn wrote:
> On 25/02/2011 19:21, Kyle Girard wrote:
>
> > I was hoping to see the assignment.
>
> > Looking at the gimple output there is no way to see that 'a' was
> > assigned in bar(). So that it can be used in wik(). Am I
> > misunderstanding someth
On Fri, Feb 25, 2011 at 11:33:58AM -0800, Andrew Pinski wrote:
> On Fri, Feb 25, 2011 at 11:21 AM, Kyle Girard wrote:
> >
> >> That *is* the content of the bar method. What exactly do you expect to
> >> see
> >> happening when you assign a class with no members? There's nothing to do!
> >
> >
On 25/02/2011 19:21, Kyle Girard wrote:
> I was hoping to see the assignment.
> Looking at the gimple output there is no way to see that 'a' was
> assigned in bar(). So that it can be used in wik(). Am I
> misunderstanding something shouldn't there be a way to see the
> assignment in bar? Do I
On Fri, Feb 25, 2011 at 11:21 AM, Kyle Girard wrote:
>
>> That *is* the content of the bar method. What exactly do you expect to see
>> happening when you assign a class with no members? There's nothing to do!
>
>
> I was hoping to see the assignment. My example might have been a little
> too
> That *is* the content of the bar method. What exactly do you expect to see
> happening when you assign a class with no members? There's nothing to do!
I was hoping to see the assignment. My example might have been a little
too simple. Here's a slightly more complex example:
foo.hh
clas
On 25/02/2011 15:20, Kyle Girard wrote:
> foo.hh
> ==
>
> class A
> {
> };
>
> class foo
> {
> A a;
> public:
> void bar(A & aa);
> };
>
>
> foo.cc
> ==
>
> #include "foo.hh"
>
> void foo::bar(A & aa)
> {
> a = aa;
> }
>
>
> However the gimple generated via g++-4.5 -c -fdum
I have the following code:
foo.hh
==
class A
{
};
class foo
{
A a;
public:
void bar(A & aa);
};
foo.cc
==
#include "foo.hh"
void foo::bar(A & aa)
{
a = aa;
}
However the gimple generated via g++-4.5 -c -fdump-tree-gimple foo.cc
is this:
void foo::bar(A&) (struct foo * co
