[EMAIL PROTECTED] wrote:
>
> #include
> #include
>
> int main()
> {
> printf("\n %1.55f \n", sqrt(3.));
> return 0;
> }
>
> Result: 2
>
> Why does this return 2 ??
If you meant to use long double, you should have so specified. Decimal
digits beyond 17 aren't significant in
On 10/25/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> Why does this return 2 ??
You should read: http://www.validlab.com/goldberg/paper.pdf which is
linked on http://gcc.gnu.org/readings.html .
Thanks,
Andrew Pinski
I use Gentoo Linux, Gcc 4.1.1 and Intel Celeron processor.
I compiled this file:
#include
#include
int main()
{
printf("\n %1.55f \n", sqrt(3.999));
return 0;
}
I get 1.999777955395074968691915273666381835 9375000
If you add one more 9 to sqrt you get 2.
#include
#
