Re: [FRIAM] the Monty Hall problem

2023-08-10 Thread Angel Edward
A even simpler explanation is that your initial pick has a 1/3 chance of winning. Nothing has changed as far as that door is concerned. Thus, with host removing one of the other two doors, the probability of winning must be 2/3. These word problems which involve a priori vs a posteriori probabi

Re: [FRIAM] the Monty Hall problem

2023-08-09 Thread Stephen Guerin
On Wed, Aug 9, 2023 at 9:19 PM Eric Smith wrote: > Wow. Old terminator. New terminator > Which one works for Skynet? The fight scene: https://youtu.be/TVA4-SNxErc?t=41 -. --- - / ...- .- .-.. .. -.. / -- --- .-. ... . / -.-. --- -.. . FRIAM Applied Complexity Group listserv Fridays 9a-12p

Re: [FRIAM] the Monty Hall problem

2023-08-09 Thread Eric Smith
Wow. Old terminator. New terminator. > On Aug 10, 2023, at 12:15 PM, Stephen Guerin > wrote: > > I think this might be a more concise explanation: > > Switching wins if you initially pick a goat (2/3 chance) and loses if you > pick the car (1/3 chance), so the win probability with switching

Re: [FRIAM] the Monty Hall problem

2023-08-09 Thread Stephen Guerin
I think this might be a more concise explanation: Switching wins if you initially pick a goat (2/3 chance) and loses if you pick the car (1/3 chance), so the win probability with switching is 2/3. ___ stephen.gue...@simtable.com