> > My question is:
> > Is it not possible, that vkbd_dev_intr() could be
> > interrupted at any position before the VKBD_LOCK()
> > and then vkbd_dev_write() called?
>
> in theory it is possible.
>
> > If yes, how should vkbd_dev_write() know, that it should
> > call task_enqueue(), as TASK is s
Norbert,
When looking at /sys/dev/vkbd/vkbd.c I found
one thing, that I do not understand.
There are three places, where a flag TASK is used:
1. in vkbd_dev_close():
while(state->ks_flag & TASK) VKBD_SLEEP (...);
2. in vkbd_dev_write()
VKBD_LOCK ();
...
if (!(state->ks_flags & TASK)
Hello.
When looking at /sys/dev/vkbd/vkbd.c I found
one thing, that I do not understand.
There are three places, where a flag TASK is used:
1. in vkbd_dev_close():
while(state->ks_flag & TASK) VKBD_SLEEP (...);
2. in vkbd_dev_write()
VKBD_LOCK ();
...
if (!(state->ks_flags & TASK) &&
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