Hello,
I have a peace of code that demonstrates that in the TP mode of
freepascal, one can use a function as a procedure.
Is this a bug or a normal behavior?
My University have replaced ( other time ) freepascal.org, and we
must use the archaic Turbo Pascal 6.0, cause they say that freepascal
d
Daniël Mantione:
Funny. Free Pascal does not respect ISO Pascal, because it respects
Turbo Pascal. :) Turbo Pascal in turn, does not respect ISO Pascal,
because it respects UCSD Pascal.
Is very confusing when talking about Standard Pascal, cause it's not
like C/C++ that have standard that is
Some time ago, I posted about this.
On the TP mode FreePascal can use a function as a procedure. Florian
told me that that was because of the version of the TP emulation.
Well, after that, I was happy with that until now. I discovered that,
even adding {$x-} to the code, if you put a function ins
I have something like this:
PStruct = ^Struct;
Struct = record
num: integer;
end;
I have a unit to handle that structure ( is a bit more complicated, but
is a good example), in this unit I have a procedure that deletes (
disposes ) the pointer. How can I know if a pointer a
Maybe I haven't explain it correctly. What I want is to construct a
Unit that contains some procedures, one of them is
create(var p : PStruct), and other is delete(var p : PStruct).
I don't create anything, the memory is allocated by the create
procedure. How can the procedure know if the argumen
It's possible to give a default initialization value to a defined type?
I suppose that it isn't, but it would be to easy to resolve that trouble
that way.
Anyway, I appreciate your help and support.
Thanks.
Zaka.
Jonas Maebe escribió:
It cannot know that without help. You have to do such book
