On Sat, 31 Dec 2022, Anthony Walter via fpc-pascal wrote:
That's pretty damn amazing. It would be even more amazing if it could read
information from the Internet and was accessible from from some API.
Imagine being able to ask it to read all the source code from a git
repository and convert
> On Dec 31, 2022, at 3:43 PM, Mattias Gaertner via fpc-pascal
> wrote:
>
> Not supported. Has nothing to do with the parameter list.
That’s disappointing. :( More reason we need an “advanced objects” mode switch.
Regards,
Ryan Joseph
___
fpc-pasc
> On Jan 1, 2023, at 6:43 AM, Anthony Walter via fpc-pascal
> wrote:
>
> The following page hosts a series of Pascal programming questions I asked an
> AI chatbot system while testing its abilities.
>
I’ve been testing using Chat GPT for work and it’s proving to be a better
solution than s
I have a simple example that gives an access violation on the latest
macos (fpc mode, i.e. no mode switch). What am I missing? Thanks in advance:
program ex;
uses fgl;
var d: specialize TFPGMap;
begin
decode.create;
decode.add('X', 1);
end.
An unhandled exception occurred at $000
> On Jan 2, 2023, at 6:57 AM, ppadilcdx--- via fpc-pascal
> wrote:
>
> program ex;
>
> uses fgl;
>
> var d: specialize TFPGMap;
>
> begin
>decode.create;
>decode.add('X', 1);
>
> end.
This doesn’t make sense. It should be
d := specialize TFPGMap.Create;
Right? What is “decode”
Sorry copy and paste error. d = decode. Corrected below. But I think I
see what you mean. Just assigning a type to decode doesn't initialize
it. But the compiler is happy with it, i.e. it doesn't call as illegal
the statement "decode.create".
On 1/1/23 5:21 PM, Hairy Pixels via fpc-pascal wr
> On Jan 2, 2023, at 8:29 AM, ppadilcdx--- via fpc-pascal
> wrote:
>
> Sorry copy and paste error. d = decode. Corrected below. But I think I see
> what you mean. Just assigning a type to decode doesn't initialize it. But
> the compiler is happy with it, i.e. it doesn't call as illegal the
ppadilcdx--- via fpc-pascal schrieb am
Mo., 2. Jan. 2023, 02:29:
> Sorry copy and paste error. d = decode. Corrected below. But I think I
> see what you mean. Just assigning a type to decode doesn't initialize
> it. But the compiler is happy with it, i.e. it doesn't call as illegal
> the statem
