On 28/10/17 23:54, Darius Blaszyk wrote:
Thanks! This is in line with what I was suspecting. However, why in the
world does the compiler not warn in this case. This should be at least
happening I would suppose?
Darius
Vojtěch Čihák schreef op 28 okt '17:
Overloading means that you have funct
Thanks! This is in line with what I was suspecting. However, why in the
world does the compiler not warn in this case. This should be at least
happening I would suppose?
Darius
Vojtěch Čihák schreef op 28 okt '17:
> Overloading means that you have functions with the same name but different
>
Overloading means that you have functions with the same name but different
parameter (or param. list). You can have different return type for each
parameter but you can never have the same parameters.
V.
__
Od: Darius Blaszyk
Komu: FP
