Am 11.11.2021 um 02:52 schrieb Ryan Joseph via fpc-pascal:
On Nov 9, 2021, at 1:09 PM, Sven Barth via fpc-pascal
wrote:
No, because the function that is called with a function pointer needs to be
inlined itself (thus becoming part of its caller) so that constant propagation
works at all fo
> On Nov 9, 2021, at 1:09 PM, Sven Barth via fpc-pascal
> wrote:
>
> No, because the function that is called with a function pointer needs to be
> inlined itself (thus becoming part of its caller) so that constant
> propagation works at all for the parameters. If a function isn't inlined the
