Thanks for the link, looks really good and I will try it out for sure as
soon as possible!
Best regards,
Marc
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Am Mi., 13. Feb. 2019, 07:06 hat Zamrony P. Juhara via fpc-pascal <
fpc-pascal
Hi, everyone
I just want to announce web application framework that I am developing, in case
anyone interested.
Not yet mature but beginning to take shape.
Source code
fanoframework/fano
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fanoframework/fano
Pascal web application framework. Cont
On 12/02/2019 19:46, Marc Santhoff wrote:
On Tue, 2019-02-12 at 17:36 +0100, Sven Barth via fpc-pascal wrote:
Not every LazLogger user knows that their code is run in a thread. And not
every thread user knows that the code they are using is using LazLogger in
turn.
Ok.
But if used that way, w
On Tue, 2019-02-12 at 17:36 +0100, Sven Barth via fpc-pascal wrote:
> Not every LazLogger user knows that their code is run in a thread. And not
> every thread user knows that the code they are using is using LazLogger in
> turn.
Ok.
But if used that way, would LazLogger need to notice at all?
On 12/02/2019 16:56, Marc Santhoff wrote:
".DeregisterThread()" method.
So you now the threads and their lifetime inside the logger.
Yes, I wanted to avoid that. Put as little on the user as possible.
The user may use some THttpRequest.OnProgress which may be in a thread,
but the user does no
Am Di., 12. Feb. 2019, 16:56 hat Marc Santhoff
geschrieben:
> On Mon, 2019-02-11 at 10:21 +, Michael Schnell wrote:
> > > Yes, but how do I get notified, when the thread is gone, and I can free
> > > the
> > > memory (of the object that was created)?
> >
> > Ah, now I finally see the problem
On 11/02/2019 11:21, Michael Schnell wrote:
Yes, but how do I get notified, when the thread is gone, and I can free the
memory (of the object that was created)?
Ah, now I finally see the problem :)
The only idea that comes in my mind is creating yet another thread or a TTimer (by means
of "Que
On Mon, 2019-02-11 at 10:21 +, Michael Schnell wrote:
> > Yes, but how do I get notified, when the thread is gone, and I can free
> > the
> > memory (of the object that was created)?
>
> Ah, now I finally see the problem :)
>
> The only idea that comes in my mind is creating yet another thread
