excellent thank you very much
On 19 mayo, 12:26, Fabio Lemos wrote:
> You have to enclose your parameter in ': see below;
> "SELECT user_code FROM ousr WHERE user_code= '" & busca & "'"
>
> 2009/5/19 Erikito1981
>
>
>
>
>
> > Hello everyone
>
> > I have a problem, I have this code which works
You have to enclose your parameter in ': see below;
"SELECT user_code FROM ousr WHERE user_code= '" & busca & "'"
2009/5/19 Erikito1981
>
> Hello everyone
>
> I have a problem, I have this code which works fine me if I use is the
> field number but if the data is character sends me an error mess
