On Jul 12, 2007, at 7:23, Cecil Westerhof wrote:
And when I put ';S' after the formula, I get the same as with nothing
after the formula.
Why this error by ';N'?
Also what is the meaning of the strange expansion by concat? Maybe not
neccesary, but I like to understand what is happening.
When y
Op do, 12-07-2007 te 01:04 -0500, schreef Eddward DeVilla:
> On 7/12/07, Cecil Westerhof <[EMAIL PROTECTED]> wrote:
> > Yes, it looks like it works completly. (What I am missing is a knowledge
> > of Lisp. Thus that will come.)
> >
> > One thing bugs me. I am used to end a formula ending with ';N'.
On 7/12/07, Cecil Westerhof <[EMAIL PROTECTED]> wrote:
Yes, it looks like it works completly. (What I am missing is a knowledge
of Lisp. Thus that will come.)
One thing bugs me. I am used to end a formula ending with ';N'.
By default the field values are passed to the lisp expression as a
stri
Op wo, 11-07-2007 te 16:59 -0500, schreef Eddward DeVilla:
> I take that back. I think it is right. I thought hard coded and
> frodatum were supposed to match. Unfortunately, it looks like the
> mailed mangles the formula line.
>
> On 7/11/07, Eddward DeVilla <[EMAIL PROTECTED]> wrote:
> > Is t
I take that back. I think it is right. I thought hard coded and
frodatum were supposed to match. Unfortunately, it looks like the
mailed mangles the formula line.
On 7/11/07, Eddward DeVilla <[EMAIL PROTECTED]> wrote:
Is this any better. I don't think it's entirely right yet.
|---+--
Is this any better. I don't think it's entirely right yet.
|---++++|
| | datum | from datum | hard coded ||
|---++++|
| # | 2007-01-01 | 1 | 1 | 2007-01-01
I have the following table:
|---++---++--|
| | datum |from datum | hard coded |
|
|---++
