Thanks for the example and your info about fd4.
Durk
> Durk Strooisma wrote:
>> Okay, thanks for verifying. What kind of scripting language would you
>> suggest for checkpassword instead?
>
> Perl works for me. Extract from such script:
>
>use constant CHECKPASSWORD_MAX_LEN => 512;
>[...]
>> read -d '\0' -r -u 3
> You are missing the correct syntax to interpret backslash escapes here:
>
> read -d $'\0' -r -u 3
>
> will work.
Thanks a lot!! I was indeed missing the $ sign! And it is nicely documented
here:
http://www.gnu.org/software/bash/manual/bashref.html#ANSI_002dC-Quoting
I n
Durk Strooisma wrote:
> Okay, thanks for verifying. What kind of scripting language would you
> suggest for checkpassword instead?
Perl works for me. Extract from such script:
use constant CHECKPASSWORD_MAX_LEN => 512;
[...]
my $input = IO::Handle->new_from_fd(3, "r");
if (not def
Hello Durk,
Am Montag, 12. Januar 2009 schrieb Durk Strooisma:
> I'm trying to implement checkpassword authentication with a simple bash
> script. In some way I can't get the password from file descriptor 3.
>
> The start of script looks like this:
>
> #!/bin/bash
>
> read -d '\0' -r -u 3
You a
> On Mon, 2009-01-12 at 20:54 +0100, Durk Strooisma wrote:
>> > On Mon, 2009-01-12 at 18:31 +0100, Durk Strooisma wrote:
>> >> #!/bin/bash
>> >>
>> >> read -d '\0' -r -u 3
>> >
>> > Are you sure this is supposed to work? \0 character is an
>> > end-of-string character in C language, and I wouldn't
On Mon, 2009-01-12 at 20:54 +0100, Durk Strooisma wrote:
> > On Mon, 2009-01-12 at 18:31 +0100, Durk Strooisma wrote:
> >> #!/bin/bash
> >>
> >> read -d '\0' -r -u 3
> >
> > Are you sure this is supposed to work? \0 character is an end-of-string
> > character in C language, and I wouldn't be surpri
> On Mon, 2009-01-12 at 18:31 +0100, Durk Strooisma wrote:
>> #!/bin/bash
>>
>> read -d '\0' -r -u 3
>
> Are you sure this is supposed to work? \0 character is an end-of-string
> character in C language, and I wouldn't be surprised if read simply
> didn't support it as delimiter.
Well if I try to
On Mon, 2009-01-12 at 18:31 +0100, Durk Strooisma wrote:
> #!/bin/bash
>
> read -d '\0' -r -u 3
Are you sure this is supposed to work? \0 character is an end-of-string
character in C language, and I wouldn't be surprised if read simply
didn't support it as delimiter.
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