I'm wondering if someone can help me out with a similar problem. I'm
trying to save to 2 different models (Order and Order_Detail, where in
Order_Detail there is a foreign key to Order) from one click of the
Submit button. How would I distinguish the POSTed data between which
form fields belong to
So when data containing fields from both models get POSTed. I would
write (pseudo) code like so ?:
if request.method == 'POST':
...
Orders = form_for_model(Order)
f = Orders(prefix='orders')
Order_Details = form_for_model(Order_Detail)
f2 = OrderDetails(prefix='order_details')
...
f.save()
f2.sav
Try removing the "core = True" in this line:
image = models.ImageField(upload_to = 'section/image/',
core = True)
I had a similar, if not exact, problem that I posted about a month and
a half ago.
--~--~-~--~~~---~--~~
You received
Have you tried moving core=True to the foreignkey field?
Tell me if this works.
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.co
This is my view code for this implementation:
if request.method == 'POST':
form1 = form_for_model(Order)
Orders = form1(request.POST, prefix='orders')
form2 = form_for_model(Order_Detail)
Orders_Details = form2(request.POST, prefix='order_details')
if Orders.is_valid():
Hi guys,
I've got this piece of javascript code in my template file which is
supposed to show an image upon a checkbox toggle:
function show_img(suf, val) {
img = document.getElementById('image_' + val);
img.src = 'media/images/schematics/SKU' + suf + '.jpg';
}
The i
You've answered your question intended for me :P
I've tried serving static files with as many combinations as I could
think of in the following form:
(r'^images/schematics/(?P.*)$', 'django.views.static.serve',
{'document_root': '/www/htdocs/gfs_chefrevival/images/schematics'}),
and matched it w
> I don't mean to offend you, but I think you've misunderstood how the
> web works. There's really no difference in the HTTP request of a
> human clicking a link and the HTTP request caused by an image tag (or
> javascript image.src assignment).
I thought that way because I couldn't find any ot
Hopefully you guys can spot an error I've not been able to. This is
the error I get:
AttributeError at /vendor/Chef/1/
'Order_DetailForm' object has no attribute 'save'
Request Method: POST
Request URL: http://192.168.1.104:8000/vendor/Chef/1/
Exception Type: AttributeError
Exception Value: 'Orde
Hi Malcolm,
This is my traceback errors from copy&paste:
Traceback (most recent call last):
File "/usr/lib/python2.4/site-packages/django/core/handlers/base.py"
in get_response
74. response = callback(request, *callback_args, **callback_kwargs)
File "/www/htdocs/gfs_chefrevival/../gfs_chefrevi
I've also tried abandoning form_for_model and created my own custom
form like so in forms.py:
from django import newforms as forms
from django.newforms.widgets import *
class OrderDetailForm(forms.Form):
order = forms.IntegerField()
quantity = forms.IntegerField()
unitPrice = FloatField(la
Yes, Alberto is right.
Also, I ran into this problem a few days ago. Basically, after you
write your view processing like Alberto suggested, you need to do a
response redirect or HttpResponseRedirect and pass it "." (which is to
the same page the user was on). After I did that on my form, the use
In python shell I typed:
>> from gfs_chefrevival.shop.forms import OrderDetailForm
>> from django import newforms as forms
>> f = OrderDetailForm()
>> f.is_bound
I get the error:
Traceback (most recent call last):
File "", line 1, in ?
AttributeError: 'lineItemPrice' object has no attribute 'i
You tried, thanks!
The errors I get come before any major piece of code. They come after
some simple statements:
OrderDetailForm = form_for_model(Order_Detail)
f = OrderDetailForm()
f.save()
f.is_bound
which means my 0.96-pre (not a typo :) ) version might not be up to
the challenge of newforms.
.
Regards,
Robo
ps: thanks everyone who tried to help!
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
To unsubscribe
Hi,
Have any of you guys imported excel/cvs by using Python/Django? I need
to import 1000 products for a shopping site and I'd like to learn the
fastest and easiest way to do so.
Is there any free/shareware programs you guys would recommend?
Thanks.
--~--~-~--~~~--
the
fieldname1 to fieldname3 would be the data from "first", "last", and
"phone"?
**Amirouche, your method is similar to Ben's, could you give me some
examples?
Thanks
-Robo
--~--~-~--~~~---~--~~
You received this message beca
t
cursor.execute("""
INSERT INTO people
(first, last, phone, email)
VALUES
(%s, %s, %s, %s)
""", (data_first, data_last, data_phone, data_email)
)
return "Job Finished"
This
e its
catching blank/empty lines because the print statements aren't
executed.
What is the appropriate way to catch blank/empty lines?
Thanks,
- robo
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django
Wow, your tip works like a charm.
Do you personally know of a good tutorial that teaches things like
this? I'd like to read them.
Thanks,
- robo
On Aug 24, 2:54 pm, Boris Samorodov <[EMAIL PROTECTED]> wrote:
> Hi, All!
>
> On Fri, 24 Aug 2007 21:05:07 - robo wrote:
>
I have to temporarily settle for this fix. That's 1
problem, the other is that only one caption gets displayed for all
images shown, and I can see why because pict.caption never iterates.
How can I display images along with their distinct caption?
Thank you in advance,
robo.
--~--~-
Hi everyone, I've set up my code to display a page that shows all
categories and projects belonging to each category. Pseudo code like
so:
for category in category
for project in project
ifequal project.category_id category.id
{{project.title}}
endifequal
endfor
endfor
Right no
Hi Kelvin,
> You could limit the list from the query ... Model.objects.all()[:2]
I have tried Project.objects.all()[:3] in hopes that the 3rd time
through the loop, it would show the "see more ..." link. But what this
actually gives me is the first 3 projects, not 3 projects for each
category. H
I assume you guys also know python. If so, I wish to get some help
with this implementation:
What I want to return is a new variable each time through the for
loop:
catQuantity = len(categoryList)
for x in catQuantity:
cat(x) = get_object_or_404(Category, cat_order=x)
return cat(x)
Thi
Great ideas! Thanks Kelvin. I'll definitely try it out and post the
results here,
robo
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email
Hi everyone. for the code below at
http://www.djangoproject.com/documentation/forms/
def create_place(request):
manipulator = Place.AddManipulator()
if request.method == 'POST':
# If data was POSTed, we're trying to create a new Place.
new_data = request.POST.copy()
Thanks guys!
I will mess around with it more to get the feel.
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
To unsubscribe
hrPost(form_data);
}
Right now the way my template displays JSON is by using innerHTML as
above. But I would like to convert the data somehow so that Django can
iterate in the {{...}} syntax.
Thanks,
robo
--~--~-~--~~~---~--~~
You received this message becaus
Hi Richard,
Can you give an example of what you are suggesting?
> One thing that you can do is to pass a
> render_to_response call a template and the python dictionary you want
> modified and let django work its majic on it before returning the
> '._container' to the page via json.
Thanks.
To
Hi Richard,
I think I got the idea of your view. What I'd like to see is an
example of your template and javascript to see how you are accessing
the json data.
Thanks a lot,
robo
--~--~-~--~~~---~--~~
You received this message because you are subscribed t
n, I ALWAYS get errors no matter what. The
code is as simple as this:
def ajax_form_test(request):
data = Manager.objects.all()
return HttpResponse(simplejson.dumps(data), mimetype="application/
javascript")
Help me solve this bizzare mystery!
Thanks,
robo
--~--~-~--~~~-
Hmm ... I tested these in non-Django templates and Django itself gave
me no errors. But now that I've tested it on a Django template, it's
giving me "Decimal("0.00") is not JSON serializable" errors.
--~--~-~--~~~---~--~~
You received this message because you are
nt to use it:
from dev_gfs.shop.json import json_encode
def hello():
return HttpResponse(json_encode(OrderDetail.objects.all()),
mimetype="application/javascript")
To Russel: you said that this decimal serialization issue was fixed a
long time ago. How so?
33 matches
Mail list logo
