Hi
maybe this is trivial, but i can't find a way to get it (and from what
i can see it seems not possible):
my model:
class Project(models.Model):
name = models.CharField('name', max_length=255)
#relationship
projectowner = models.ForeignKey(Person)
in admin
Daniel,
thanks a lot, it works perfectly
Paolo
On Nov 17, 8:19 pm, Daniel Roseman <[EMAIL PROTECTED]>
wrote:
> On Nov 17, 4:42 pm, Paolo Corti <[EMAIL PROTECTED]> wrote:
>
>
>
> > Hi
> > maybe this is trivial, but i can't find a way to get it (and from
cess the object I just created from the admin interface:
http://localhost:8000/admin/apptestutf/person/6/
I get this error:
TemplateSyntaxError at /admin/apptestutf/person/6/
Caught an exception while rendering: 'ascii' codec can't encode
character u'\xe8
just created from the admin interface:
http://localhost:8000/admin/apptestutf/person/6/
I get this error:
TemplateSyntaxError at /admin/apptestutf/person/6/
Caught an exception while rendering: 'ascii' codec can't encode
character u'\xe8
On 1 Set, 18:48, Malcolm Tredinnick <[EMAIL PROTECTED]> wrote:
> On Mon, 2008-09-01 at 08:37 -0700, PaoloCortiwrote:
> > Hi all
>
> > I am a beginner using Django from the trunk and Postgres 8.2
>
> > I have this issue with utf8, you can replicate it this way (it is
> > something similiar to thi
Hi
here is a sample class:
class TipoMisura(models.Model):
nome = models.CharField('nome', max_length=255, null=True)
class Meta:
verbose_name = "Tipo di Misura"
verbose_name_plural = "Tipo di Misure"
In the admin interface, the link to the chang
Hi
I know is easy to access to the UserProfile, like here:
from django.contrib.auth.models import User
u = User.objects.get(pk=1) # Get the first user in the system
user_address = u.get_profile().home_address
but is there a way to access to UserProfile in the view?
supposing the UserProfile mode
Hello Andy
>
> Do you mean in the template?
yes, sorry...
>
> I don't use Django templating but have you tried:
>
> user.get_profile.home_address
>
if i use this in the template i get this error: Caught an exception
while rendering: Cannot resolve keyword 'user' into field
thanks anyway
On Mar 17, 7:24 pm, Andy Mckay wrote:
> If you use request context then you will get the user available:
>
> http://docs.djangoproject.com/en/dev/ref/templates/api/?from=olddocs#...
I could correctly access context, in fact i had the error also from
the shell.
The problem i had ("Caught an exc
Hi
is it possible to update an object with a dictionary?
I tried something like this:
myobject.save(force_update=True, **my_dict)
getting an error, though:
TypeError at ...
save() got an unexpected keyword argument 'myfieldname'
I wouldn't like to iterate the dictionary, neither to delete and
c
>
> .save() is only for persisting the object to disk, not for modifying
> objects. To update any Python object from a dictionary is as easy as:
>
> for k,v in d.items(): setattr(myobject, k, v)
this is also what i came to.
But curious to try the Daniel's approach, will let you know
best regards
the active
operation end
I am having the same behavior both with Django 1.2.5 and 1.3 RC
any ideas?
thanks
--
Paolo Corti
Geospatial software developer
web: http://www.paolocorti.net
twitter: @paolo_corti
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On 22 Mar, 11:41, Paolo Corti wrote:
> Hi
> I had to migrate a GeoDjango project based on a Postgres/PostGIS
> backend to a Oracle/Oracle Spatial backend.
>
> I could sync the database without problems and now I can successfully
> read and create new data from the shell, but a
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