I think a more common case is programmer error, you may yourself harm the
system because of a bug you introduced, I once deleted a folder one level
too high (deleted the parent folder of the folder I intended to delete)
if the user only had permissions to only what it is supposed to do I would
just
Thanks for the good explanation as always :)
From the documentation plus the explanation of the problem,
I wanted to know if by deleting the old migration it would still
run the old migrations.
Do we know the end of the story? Where it comes from?
Thanks
On 06/12/2015 05:42 PM, Carl Meyer wrot
Forgot about ModelChoise.
Thank you.
On Sunday, 14 June 2015 22:37:26 UTC+3, Tom Evans wrote:
>
> On Sun, Jun 14, 2015 at 3:24 PM, Mark Nesterovych
> > wrote:
> > Hello.
> > I've just finished small django site, and keep going on creating tests.
> > I've found and issue with Model.objects.valu
I have a model to write blogs. In that I'm using a wysiwyg editor for the
Blog's descritpion, through which I can insert an image within the
description.
class Blog(models.Model):
title = models.CharField(max_length=150, blank=True)
description = models.TextField()
pubdate = models.Dat
Hi,
So the original problem was that I was running in the repo which didn't
have the squashed migration. Django does know when to switch to the
squashed migrations when you have both squashed and unsquashed migration
files coexist in the folder.
As for the syntax error it was because python can
If the description is stored as HTML I guess you could use something like
BeautifulSoup or pyquery to parse it and find the tag
from bs4 import BeautifulSoup
soup = BeautifulSoup(blog.description)
image_src = soup.find('img')['src']
On Mon, Jun 15, 2015 at 8:59 AM, Robin Lery wrote:
> I have
Great.
Thanks for the feedback :)
On 06/15/2015 02:18 PM, Cherie Pun wrote:
Hi,
So the original problem was that I was running in the repo which
didn't have the squashed migration. Django does know when to switch to
the squashed migrations when you have both squashed and unsquashed
migratio
very nice work
On 6/15/15, Vijay Khemlani wrote:
> If the description is stored as HTML I guess you could use something like
> BeautifulSoup or pyquery to parse it and find the tag
>
> from bs4 import BeautifulSoup
>
> soup = BeautifulSoup(blog.description)
> image_src = soup.find('img')['src']
>
Hello, use two model and the second model inline one model example
class ModelA(...):
name = charfield(...)
class ModelB():
fk(ModelA)
image = imagefiel(...)
caption = bla bla bla
date = datefield
and them in admin.py
class ModelBInline(admin.TabularInline):
model = Mode
Hello,
This maybe a generic question. How do I troubleshoot something like this.
The stacktrace is not really helpful as it does not point to the code that
is causing this issue.
TypeError at /product/
'function' object is not iterable
Request Method:POSTRequest URL:http://127.0.0.1:8000/p
You can use celery and periodic tasks to scan for new orders every 5
minutes and send email notification of the new order is there.
On 12 Jun 2015 6:59 pm, "'Tom Evans' via Django users" <
django-users@googlegroups.com> wrote:
> On Thu, Jun 11, 2015 at 8:02 PM, Andreas Kuhne
> wrote:
> > Hi all,
Can you post the entire stack trace? You may have to run a bit up the chain
in the race to track down the problem.
-James
On Jun 15, 2015 2:40 PM, "Shekar Tippur" wrote:
>
>
>
> Hello,
>
> This maybe a generic question. How do I troubleshoot something like this.
> The stacktrace is not really he
James,
Is this what you mean?
- Shekar
> Environment:Request Method: POSTRequest URL:
> http://127.0.0.1:8000/product/Django Version: 1.8.2Python Version:
> 3.4.3Installed Applications:('django.contrib.admin', 'django.contrib.auth',
> 'django.contrib.contenttypes', 'django.contrib.sessions'
No, you need to post the parts of your code that may have triggered the
error.
In this case, your urls.py and the method in your views.py that handles the
request probably.
On Mon, Jun 15, 2015 at 9:32 PM, Shekar Tippur wrote:
> James,
>
> Is this what you mean?
>
> - Shekar
>
>
>> Environment:
Here my urls.py
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^product/$', productviews, productviews.ProductList.as_view()),
url(r'^product/(?P[0-9]+)$', productviews.ProductDetail.as_view()),
]
*productviews.py*
from product.models import Product
from product.s
That is what I meant, but the extra code is quite helpful. In your
urls.py file you have this:
url(r'^product/$', productviews, productviews.ProductList.as_view()),
when you probably want this:
url(r'^product/$', productviews.ProductList.as_view()),
You have an extra reference to 'productviews
Thank you.
On Mon, Jun 15, 2015 at 10:37 PM, carlos wrote:
> Hello, use two model and the second model inline one model example
>
> class ModelA(...):
> name = charfield(...)
>
> class ModelB():
> fk(ModelA)
>image = imagefiel(...)
>caption = bla bla bla
> date = datefield
>
> Thank you! Thank you! Thank you!
Sometimes I miss the most obvious things.
Thanks again.
- Shekar
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