Hi all,
I don't know if this is the perfect place to post this, but I couldn't
think of a better one. I'm open to suggestions.
I run my own software company in Romania and between 8th and 21st of April
I'll be in London. If there is anyone interested in having a chat face to
face please contac
One way to do it is to run all operations, don't call "save" and verify
"manually" if objects are correct.
I don't know about other methods, but if someone else does it would be
great.
On Sun, Mar 22, 2015 at 6:29 AM, Murthy Sandeep
wrote:
> Hi
>
> I have created an data migration script for pop
Can someone explain the test condition on line 31 of
https://github.com/django/django/blob/master/django/contrib/staticfiles/views.py
- Just spent a few hours trying to get my unit tests to pass and couldn't
figure out what was going on until I found this weirdness.
I understand serve() isn't mean
I see now that the behaviour of serve() was changed for 1.7 and it now
returns a silent misleading 404 result rather than the old
ImproperlyConfigured exception which would have provided a clue as to the
actual root cause.
See:
https://docs.djangoproject.com/en/1.7/ref/contrib/staticfiles/#django.
Hello,
I have this settings.py [1], and my CustomUser [2]
When I try to use in my template:
{{ user_first_name }}
don't show anything... What I miss in these code?
Regards,
[1] - https://gist.github.com/fellipeh/adbfaf06361d68650f95
[2] - https://gist.github.com/fellipeh/a0cc18f26aa9868a061
Please see https://github.com/django/django/commit/4c6ffcf7 for the
rationale for the change. I am open to ideas, but I'm concerned that
including details about the reason for the 404 might cause information
leakage in production which wouldn't be desirable.
On Monday, March 23, 2015 at 10:06:2
Do you have 'django.contrib.auth.context_processors.auth' in
your context template processor?
{{ user_first_name }} won't work anyway cause the variable
set by the context_processor auth is user. To access a key
or an attribute of a variable, the syntax is:
{{ user.first_name }}
documentation on
Yes, I have django.contrib.auth.context_processors.auth in my Tamplate
processor: here is my template processor:
TEMPLATE_CONTEXT_PROCESSORS ('django.contrib.auth.context_processors.auth',
'django.core.context_processors.debug',
'django.core.context_processors.i18n',
'django.core.context_processor
Hey Tim,
Appreciate the link. It looks like we're trying to have it go both ways
here. If we don't want to allow it into production then make it explicit
and break it - just as before. If we want to recommend that it not go into
production but then let users actually do it, don't silently break
JSON is literally the notation for objects and arrays in JavaScript, when
you "print" it it outputs valid JavaScript code.
On Mon, Mar 23, 2015 at 11:59 AM, dk wrote:
> AHHH!!!...
> that make scenes that the java script did work when I did it manually.
> I haven't use json files before, so
On Monday, 23 March 2015 14:16:00 UTC, Fellipe Henrique wrote:
>
> Hello,
>
> I have this settings.py [1], and my CustomUser [2]
>
> When I try to use in my template:
>
> {{ user_first_name }}
>
> don't show anything... What I miss in these code?
>
>
You should show your view. Are you using a Re
AHHH!!!...
that make scenes that the java script did work when I did it manually. I
haven't use json files before, so I am not sure how to manage that, I will
look around for more information on that.
On Friday, March 20, 2015 at 4:59:30 PM UTC-5, dk wrote:
> I am trying to create an au
Thanks Russell, that's clear now.
Cheers,
Dan
在 2015年3月20日星期五 UTC-5下午6:27:12，Russell Keith-Magee写道：
>
>
> On Sat, Mar 21, 2015 at 5:25 AM, Dan Dong
> > wrote:
>
>> Hi,
>> Does anybody know how to supply the input parameters to "python
>> manage.py syncdb" from a script? E.g, to set the the f
To have the decision revisited, you should raise it on django-developers.
On Monday, March 23, 2015 at 10:39:57 AM UTC-4, Ben Scherrey wrote:
>
> Hey Tim,
>
>Appreciate the link. It looks like we're trying to have it go both ways
> here. If we don't want to allow it into production then make
I found the problem, I was create a custom template context processor, and
for some reason I choose one name that override some function in one os 3rd
apps I'm using... I change the name of my custom context processor, and
works Fine!
Thanks again
T.·.F.·.A.·. S+F
*Fellipe Henrique P. Soares*
Hello,
I have these view:
def planos_view(request, cat_id=0):
if cat_id == '0':
categorias = Categoria.objects.filter(publicado=True)
else:
categorias = Categoria.objects.filter(publicado=True).filter(id=cat_id)
for c in categorias:
c.total = Plano.objects.fil
Anybody please help.
On Sun, Mar 22, 2015 at 3:07 PM, Sandeep kaur wrote:
> Greetings,
> I want to have the thumnails of images with the names in the dropdown
> field of form. To return the image as foreign key field, I have used this
> code :
> def __unicode__(self):
> image_data =
> o
Adding it as a regular property to your Categories class should work:
# inside Categoria
@property
def total(self):
return Plano.object.filter(categoria=self).count()
You may also want to use backward relationship links to simplify the
code and make it more robust, but I don't
You can't include images in the options of a typycal html dropdown
To do so you need to use JavaScript, for example this plugin
http://designwithpc.com/plugins/ddslick#demo
And pass the options in the format specified by the plugin
On Mon, Mar 23, 2015 at 1:51 PM, Sandeep kaur wrote:
> Anybod
Ok,
But, if I want to create some "fields" in RunTime, I thinking to use Dict,
but I don't know what to use to create "temporary" queryset...
T.·.F.·.A.·. S+F
*Fellipe Henrique P. Soares*
e-mail: > echo "lkrrovknFmsgor4ius" | perl -pe \ 's/(.)/chr(ord($1)-2*3)/ge'
*Blog: http://fhbash.wordpr
How to create a field with multiple values? For example an integer field
that takes on particular values:
state = models.IntegerField()
... where state=0 represents 'pending', state=1 represents 'accepted' and
state=2 represents 'rejected'.
Is it possible to put these values / constants into t
You can use an IntegerField with choices
https://docs.djangoproject.com/en/1.7/ref/models/fields/#choices
On Mon, Mar 23, 2015 at 4:28 PM, Daniel Grace wrote:
> How to create a field with multiple values? For example an integer field
> that takes on particular values:
>
> state = models.Intege
I'd also recommend using the "Choices" functionality of the Django Model
Utils project. It will give you good tools to keep the code readable,
simplify access and presentation of data:
https://django-model-utils.readthedocs.org/en/latest/utilities.html#choices
On Mon, Mar 23, 2015 at 4:34 PM, Vij
Hi,
How can I search the database using multiple parameters similar like "where
username ="myUserName" or email = "MyEmail"?
I tried to run User.object.get(username = myusername or email = myEmail),
but that caused syntax error.
Thank you.
Kind regards,
- -j
--
You received this message
from django.db.models import Q
User.object.get(Q(username=myusername) | Q(email=myEmail))
On Mon, Mar 23, 2015 at 9:30 PM, nobody wrote:
> Hi,
>
> How can I search the database using multiple parameters similar like
> "where username ="myUserName" or email = "MyEmail"?
>
> I tried to run User.o
This is my first stab at upgrading directly from Django 1.6.11 to 1.81c
to see what needs to be done. I thought I'd skip 1.7.x - is that a bad
idea? Is there some step in 1.7.x which eases the path to 1.8.x?
On first starting the project up using runserver on localhost it advises:
Python: 3.
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