Hi,
I am trying to build a menu system which can be controlled at the admin
area. For the content management purpose i am using django flatpage. So when
a page is getting saved i need to insert the page title and url in the menu
table i have created. So i guess a flatpage signal is the best way to
I recently updgraded to django 1.3. After the upgrade, I get the
following error whenever I used request.POST:
Traceback (most recent call last):
File "/usr/lib/python2.4/site-packages/django/core/handlers/base.py",
line 86, in get_response
response = None
File "/public/gdp/trunk/src/ukl/lis/pr
Hi,
I'm a bit curious about the ModPythonRequest object which makes me think you
are using mod_python.
If this is the case, you should note that its support is deprecated:
Support for mod_python has been deprecated, and will be removed in Django 1.5.
If you are configuring a new deployment, you
Hi,
I have an model which contains a CharField.
Now I want to have different subclasses of this model each one with
different *choices* for the CharFiel. How can I implement this?
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HI, Artemis,
If I understand you correctly you want to use a Select Widget for your
CharField. And feed your choices to the select widget.
In your admin.py file of your app you will want to override the model's form
field.
# models.py
from django.db import models
myModel(models.Model):
perso
HI, Artemis,
If I understand you correctly you want to use a Select Widget for your
CharField. And feed your choices to the select widget.
In your admin.py file of your app you will want to override the model's
form field.
# models.py
from django.db import models
myModel(models.Model):
pers
Hi Brian,
that works so far for displaying the correct choices in the admin
interface. But the problem now is the validation. He always tells me
that my choice is not a correct value.
I have been looking for a way to change validation but I can't figure
out how to do this...
Thanks for your help
I have setup my application to use the settings from the django
documentation on logging, with a few items removed for simplicity. I
have found that the logger django.request is not running even though I
am trying to log an error from within a view. If I add '' logger
(thanks to some other posts f
No, I had Debug=True.
Xavier, you have a good point, my understanding of STATICFILES is
still foggy, and I do have confusion between media and static files.
However, I have to make some progress on the rest of
my code. I will revisit this when I have some cycles, but for sure,
when I try to use a
I want to log ERRORs to an error log and INFO to an info log file. I
have it setup like this, but the info log files gets both INFO and
ERROR logging (because it allows INFO and above severity). How do I
only run a handler for INFO and not higher items such as ERROR.
LOGGING = {
'version': 1,
heya,
This SO post seems to suggest that data and template tags shouldn't mix...
http://stackoverflow.com/questions/5046046/where-put-database-interaction-in-django-templatetags
Not sure how I feel about that myself - I see the philosophical argument
behind it, but I don't see another more effi
Hi guys and gals,
I maintain a Django-CMS website running on Django 1.2.5 with a couple of
pages - one for selling houses, one buying houses, etc. At the moment
it's all under one domain name (http://patmat.co.nz) with some other
domains being redirected by Apache to specific pages on the main
Hi Jonas,
You can override validation by adding a "clean" method to the ModelAdmin
subclass. Look here for more details,
https://docs.djangoproject.com/en/dev/ref/forms/validation/#cleaning-and-validating-fields-that-depend-on-each-other
.
That is what I have been doing. It might be hacky, someone
On 10/02/2011 04:12 PM, Michael Ludvig wrote:
> Hi guys and gals,
>
> I maintain a Django-CMS website running on Django 1.2.5 with a couple of
> pages - one for selling houses, one buying houses, etc. At the moment
> it's all under one domain name (http://patmat.co.nz) with some other
> domains be
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