yeah i was looking at something like that... actually let me correct
what i'm needing to do:
select year(fieldname) as pubyear from table order by year(fieldname) asc
On 09/27/2010 01:15 AM, akaariai wrote:
The most efficient? Exactly that using raw SQL. I think something
along the followin
The most efficient? Exactly that using raw SQL. I think something
along the following will also work:
Foo.objects.only('fieldname').value_list().distinct().order_by('fieldname').
- Anssi
On Sep 27, 5:49 am, Bobby Roberts wrote:
> what is the most efficient way to do the following sql command in
what is the most efficient way to do the following sql command in
django?
select distinct fieldname from table order by fieldname
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