Sounds like you are looking for this: http://code.djangoproject.com/ticket/4412
On Jul 14, 12:18 pm, rskm1 <[EMAIL PROTECTED]> wrote:
> On Jul 13, 9:58 am, "Nikolay Panov" <[EMAIL PROTECTED]> wrote:
>
> > You should create your custom widget for this.
>
> Also see the thread from a couple weeks a
On Jul 13, 9:58 am, "Nikolay Panov" <[EMAIL PROTECTED]> wrote:
> You should create your custom widget for this.
Also see the thread from a couple weeks ago titled "choices",
http://groups.google.com/group/django-users/browse_thread/thread/d373794afef19e39/0009b671ebd91ac1
--~--~-~--~
Hi,
> Is there any easy way to do that? O are hint on how to do it?
You should create your custom widget for this.
Regards,
Nikolay.
On Sat, Jul 12, 2008 at 19:57, Nenillo <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> I'm doing an app with a category model. That category model has an
> autoreferenc
Misspoke in that last post--if you want a select tag, obviously you
won't be using li tags. You'd use option tags, and maybe throw in
some text in front of each option to indicate the level. Everything
else still applies the same.
-Jeff
On Jul 12, 11:57 am, Nenillo <[EMAIL PROTECTED]> wrote:
>
I recently had to do something similar. The way I went about it (and
I'm not sure this is the best way) is to select all of the categories,
then iterate through them and build a tree, using each category's
parent_id to figure out where in the tree it fits.
Then, once you've got a tree, you have
Hi,
I'm doing an app with a category model. That category model has an
autoreference field, to do multiple category levels. I'm using
models.ForeignKey('self',
null=True, blank=True) for that. The problem is that the select is
shown in a plain way and I wan to do something like:
Cat1
- Subcat1-
6 matches
Mail list logo
