No, that wouldn't work because Category looks like a var on Novel, not
a model in it's own right.
Novels.objects.filter(category="comedy") is how to get a distinct category.
To get the list of categories used, use distinct for a quick hack -
something like:
Novel.objects.order_by('category').dis
Hi dota and java,
If your model for the categories is Category, you would use:
Category.objects.all()
Sent from my iPad
> On May 23, 2014, at 23:23, dotaandj...@gmail.com wrote:
>
> i can't find a more effective method from the documentation,but thank you all
> the same
>
> 在 2014年5月23日星期五UT
i can't find a more effective method from the documentation,but thank you
all the same
在 2014年5月23日星期五UTC+8下午11时12分13秒，sacrac写道：
>
> Hi, you read the documentation?
> https://docs.djangoproject.com/en/1.6/ref/models/querysets/
>
>
> On Fri, May 23, 2014 at 6:36 AM, > wrote:
>
>> In Models i decl
Hi, you read the documentation?
https://docs.djangoproject.com/en/1.6/ref/models/querysets/
On Fri, May 23, 2014 at 6:36 AM, wrote:
> In Models i declare Novel: name,category
> table structure:
> ---
> id| name |category
>
In Models i declare Novel: name,category
table structure:
---
id| name |category
---
now i want to get all category,but i have no idea,who can help me?
my english is poor,please don't joke me
--
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