Hello,
The variable 'contact' on line 27 is messing with python as the model name
'contact' is not being recognized but instead, the variable is being
recognized.
I'd advise you to change the variable name. i.e.
contact = contact()
to
contact_var = contact(...)
contact_var.save()
[image: Ma
Declare the contact variable before the return statement
On Mon, 24 Oct, 2022, 00:52 Deepak kumar, wrote:
> please check to pdf and send to my email dk9284...@gmail.com
>
> --
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
> To unsubscribe fro
7;routing'):
>>
>> testElement =
>> ApprovedTestElement.objects.filter(testElemType=elemType,routing='Y');
>>
>> elif(elemCategory=='switching'):
>>
>> testElement =
>> ApprovedTestElem
return
> render(request,self.template_name,{'testElement':testElement,'testPlanId':testPlanId})
>
> I am trying to send a different testElement based on which if condition has
> been satisfied. I am new to Django and
'Y');
return
render(request,self.template_name,{'testElement':testElement,'testPlanId':testPlanId})
I am trying to send a different testElement based on which if condition has
been satisfied. I am new to Django and I keep getting UnboundLocalError
Excep
t;word"] = random.choice(pre_word)
> while option_key:
> option_key = random.choice(key_list)
> option_value = random.choice(pre_mean)
> pre_ques[option_key] = option_value
> key_list.remove(option_key)
> pre
t.remove(option_key)
pre_mean.remove(option_value)
context = RequestContext(request)
return
render_to_response('tag_study/test_words.html',{"pre_ques":pre_ques},
context)
*I have no idea about the error, the tracebank is *
*UnboundLocalError at /tag_study/tes
Never mind it seems using a tuple instead of a list solved my problem.
subset = df[[0, 1, 2, 'FRACTION']]
tuples = [tuple(x) for x in subset.values]
On Saturday, May 31, 2014 8:15:16 PM UTC+2, Pepsodent Cola wrote:
>
> Exception Type: UnboundLocalError Exception V
Exception Type: UnboundLocalError Exception Value:
local variable 'list' referenced before assignment
Hi, I'm trying to convert my pandas DataFrame into a simple list in
Views.py and send it to template. But Django complains and I don't know
how to make it happy
ine 147, in call_command
> > return klass.execute(*args, **defaults)
> > File "/home/rok/apps/django-trunk/django/core/management/base.py",
> > line 232, in execute
> > output = self.handle(*args, **options)
> > File "/home/rok/apps/django-trunk/dj
def gene_view(request, slug=None, gene=None, org=None, template=None):
>> print(KeyError)
>>
>> and I get this exception with django 1.4 (if it matters):
>> UnboundLocalError at /predictions/gene/
>> local variable 'KeyError' referenced before assignment
>
>
> print(KeyError)
>
> and I get this exception with django 1.4 (if it matters):
> UnboundLocalError at /predictions/gene/
> local variable 'KeyError' referenced before assignment
Python thinks KeyError is a local variable, thus it sounds like code
in the view subsequ
rror. I've actually manged to narrow it down to a pretty simple
test case though. Within the view, I can do this (first few lines):
def gene_view(request, slug=None, gene=None, org=None, template=None):
print(KeyError)
and I get this exception with django 1.4 (if it matters):
UnboundLocalE
base=db)
> File "/home/rok/apps/django-trunk/django/core/management/
> __init__.py", line 147, in call_command
> return klass.execute(*args, **defaults)
> File "/home/rok/apps/django-trunk/django/core/management/base.py",
> line 232, in execute
> outpu
handle(*args, **options)
File "/home/rok/apps/django-trunk/django/core/management/commands/
loaddata.py", line 239, in handle
(full_path, ''.join(traceback.format_exception(sys.exc_type,
UnboundLocalError: local variable 'full_path' referenced before
assignm
On 11 juin, 15:26, Marcus Whybrow wrote:
> I have found a ticket already open for this problem (http://
> code.djangoproject.com/ticket/13684),
> The problem was in fact that I had a settings.py file and a module
> called settings with default and local settings residing inside it.
If you mean "a
self.get_response(request)
> > File "/home/webapps/.virtualenvs/tinygraph/lib/python2.6/site-
> > packages/Django-1.2.1-py2.6.egg/django/core/handlers/base.py", line
> > 142, in get_response
> > return self.handle_uncaught_exception(request, resolver, exc_info)
response
> return self.handle_uncaught_exception(request, resolver, exc_info)
> UnboundLocalError: local variable 'resolver' referenced before
> assignment
>
> I have just set up a brand new Django project called tinygraph and I
> am using WSGI and virutalenv in combin
ine
241, in __call__
response = self.get_response(request)
File "/home/webapps/.virtualenvs/tinygraph/lib/python2.6/site-
packages/Django-1.2.1-py2.6.egg/django/core/handlers/base.py", line
142, in get_response
return self.handle_uncaught_exception(request, resolver, exc_info)
UnboundLocalE
Hi ALL!
Can I use threaded management commands? I write simple data import
command from manage.py. This command use threadpool and I sometimes
get UnboundLocalError on some variables (they differ) that they
referenced before assignment.. Why It can be so?
Thanks
ite-packages/mod_python/importer.py", line
1537, in HandlerDispatch
default=default_handler, arg=req, silent=hlist.silent)
File "/usr/lib/python2.5/site-packages/mod_python/importer.py", line
1206, in _process_target
object = apache.resolve_object(mo
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