On Nov 7, 4:11 pm, jago <[EMAIL PROTECTED]> wrote:
> Sure.
>
> {% for gallerykind in gallerykinds %}
>
> {{ gallerykind.title }}
>
> {% if gallerykind.author %}
>
Sure.
{% for gallerykind in gallerykinds %}
{{ gallerykind.title }}
{% if gallerykind.author %}
by {{ gallerykind.author }}
On Nov 7, 2:12 pm, jago <[EMAIL PROTECTED]> wrote:
> I tried the slice solution before. Unluckily it returns a list itself
> holding 1 item instead of the item itself. Most importantly though I
> cannot use a variable like forloop.counter0 to select the item I want
> but instead can only use stati
I tried the slice solution before. Unluckily it returns a list itself
holding 1 item instead of the item itself. Most importantly though I
cannot use a variable like forloop.counter0 to select the item I want
but instead can only use static numeric values like 1,2,3
On Nov 7, 10:39 am, Daniel Ros
Obviously I want to select for each iteration another item from the
array. Unluckily something like:
arr.forloop.counter0
forloop.counter0 is the variable that holds the currently used index
in a for loop: http://www.djangoproject.com/documentation/0.96/templates/#for
Any idea how I could selec
On Nov 7, 12:52 am, jago <[EMAIL PROTECTED]> wrote:
> I have a for loop over a list A.
>
> inside the loop I want to print out the item of list B at the index
> 'forloop.counter0' of list A.
>
> It is really strange. One can select randon items in a list, or the
> first item in a list, but I did n
You can use something like {{ array.index}} to get the value of a
specific index.
For e.g.
arr = [1,2,3,4]
In view, if I do a
{{ arr.1 }}, it should return 2
-- Raja
On Nov 7, 5:52 am, jago <[EMAIL PROTECTED]> wrote:
> I have a for loop over a list A.
>
> inside the loop I want to print out t
The is not way to get list item by variable index with standard django
template tags.
On Fri, Nov 7, 2008 at 03:52, jago <[EMAIL PROTECTED]> wrote:
>
> I have a for loop over a list A.
>
> inside the loop I want to print out the item of list B at the index
> 'forloop.counter0' of list A.
>
> It
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