>
> >> number_of_meds = kwargs.pop('number_of_meds', 4)
>
> This is how I optionally passed the number of
> fields I wanted to display in the form. If there's
> no 'number_of_meds' in kwargs, a minimum of 4 fields
> are displayed. The trick is to use kwargs.pop() before
> super is called, or you
On Mar 15, 12:30 pm, "Tipan" <[EMAIL PROTECTED]> wrote:
> Realised my daft error in creating the dictionary. I've resolved that
> now and can happily pass the queryset data to the Form class by
> creating the dict. However, I'm still not sure how to pass the number
> of records to the Form class.
[reference: http://www.djangosnippets.org/snippets/82 ]
Tipan,
>From your code I think you may be confusing a dictionary
key with a list index.
> data_list=UserPoints.objects.filter(user = myuser)
> for i in data_list:
> k='type_%d' % i
> l='points_%d' % i
Note in line #28 how I'm defi
Realised my daft error in creating the dictionary. I've resolved that
now and can happily pass the queryset data to the Form class by
creating the dict. However, I'm still not sure how to pass the number
of records to the Form class.
Can you advise?
Tim
--~--~-~--~~~--
> I've posted a code snippet that I think addresses your
> issue:http://www.djangosnippets.org/snippets/82/
>
Jeff, this was very helpful and I've moved on a bit, I can make your
form do exactly what it's supposed to. Howver I'm still struggling to
pass my information to the Form class.
I note t
Tipan,
I've posted a code snippet that I think addresses your
issue: http://www.djangosnippets.org/snippets/82/
--
Jeff Bauer
Rubicon, Inc.
--~--~-~--~~~---~--~~
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I wonder if anyone can give me some pointers. I've been working with
new forms with reasonable results, but I've come across a problem when
creating a form with dynamic fields and rendering to an HTML template.
I want to create a form using data from a queryset which extracts data
for a specific
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